[codejunkie12]

Hey all, I'm trying to randomize a bunch of numbers into an integer array however when I do, I get a "possible loss of precision error", I can change my tempNum variable to double however I wish to use an integer array, is there a way to fix this? My code is below:

public class Main {

    public static void main(String[] args) {
       int [] numbers = new int [10];
       for (int i = 0; i < 10; i++) {
           int tempNum = Math.random() * 20; //possible loss of precision error?
        }
       for (int i = 0; i < 10; i++) {
           System.out.println ("Number " + i + " : " + numbers[i] );
           
       }
    }

}

[g00se]

You need an explicit cast

int tempNum = (int)(Math.random() * 20);

[mi14chal]

If you get int not double you'll should use class Random. In class Random is found function which is return int. You can see example code: http://www.javapract...Action.do?Id=62

[sakshamkum]

Math.random() returns a double type answer and you need to store it in an Integer array. to do it just type cast it

[codejunkie12]

Oh... ok, what exactly does this casting do? My code works now but I'm not 100% sure as to what the code does? Sorry I'm new to java.

[sakshamkum]

casting converts data from one type to another. see java tutorials for more reference.

[codejunkie12]

Thanks! Wow this website is awesome

[v0rtex]

We all knew that it was! Casting basically takes data that was stored in memory as a certain data structure and then stores it in memory with the same size (generally) but as a different data type, the old data is lost when you cast the variable. Concerning your randomizing of integers using Math.random(), this may provide a better explanation.
http://www.java-exam...ing-math.random

[codejunkie12]

Thanks, I have basically gathered that: the "(int)" parses the double of Math.random()*n to an int value.