[ctcoyote16]

Hello guys. I am in a C++ class and I'm having trouble with this assignment. The assignment is to Enter a string and use a loop to find the ASCII Number of its characters.

We've been dealing with "For Loops" so basically this code needs to contain at least one.

Heres all I can think to figure out:

cout<<"Enter a word: ";
cin>>word;

for(int i=0; i>word.length; i++)

word.find()

Yeah, I dont really understand this and Im not sure what exactly needs to be in it but Im pretty sure Ill need the substr, length, and find functions.

Any help is greatly appreciated. Thanks

[realNoName]

Quote

The assignment is to Enter a string and use a loop to find the ASCII Number of its characters.

I dont really know what your wanting... something you need to fix is to use the length function you need to add () ex word.length() as for getting the ASC-II value one of the ways to do it is a static cast

static_cast<int>(word[i])

[Ryan747]

cout<<"Enter a word: ";
cin>>word;

for(int i=0; i<word.length(); i++){
   cout << int(word[i]);
}

i think this is what you meant....

[born2c0de]

Yes, Ryan747 is right.
Internally, everything is a number. There's no such thing as a character. Characters are stored as integers in memory where each integer value corresponds to a character according to ASCII.

So typecasting a character into an integer does the trick.

[ctcoyote16]

alright thanks guys. I got to finish this code up tonight, its for homework. hope to learn all this stuff eventually, lol