[dylan.mann]

Anytime I use an else in an if statement my page won't load.

$x = 10;
if($x < 100) {
   echo 'True.';
}

Works fine but if I try:

$x = 10;
if($x < 100) {
   echo 'True.';
   else
      echo 'False.';
   }
}

My page won't load (HTTP 500 Error) or it will download the php file instead. Any ideas? Thanks in advance.

This post has been edited by dylan.mann: 17 June 2011 - 11:32 PM

[atik97]

the else block you have used have no corresponding if code block, thats why generating error.

$x = 10;
if($x < 100) {
   echo 'True.';
}
else {
   echo 'False.';
}

You can use nested if-else, but every time an else block must be followed by a corresponding if code block.

[CTphpnwb]

You must close braces. You can do as aitk97 has shown or because you've only got one line inside the if/else you can do this:

$x = 10;
if($x < 100) 
   echo 'True.';
else 
   echo 'False.';

or this

$x = 10;
if($x < 100) {
   echo 'True.';
}
else 
   echo 'False.';

or even this

$x = 10;
if($x < 100) 
   echo 'True.';
else {
   echo 'False.';
}

But you can't break up a pair of braces.

This post has been edited by CTphpnwb: 18 June 2011 - 03:57 AM

[dylan.mann]

Thanks all. Did notice that I had a typo in my original post. Meant for the second (non-working) example to be:

$x = 10;
if($x < 100) {
   echo 'True.';
   else {
      echo 'False.';
   }
}

[satis]

As noted previously, your code is wrong.

You have an external block that says

if($x < 100){
  [some code]
}

Then you have an internal block that says

echo 'True.';
else{
     echo 'False.';
}

This is invalid, since you can't have an else without a corresponding if first. The problem is your use of braces. The opening brace after the if is supposed to surround only the if statement... the else statement is separate. so, as noted previously:

$x = 10;
if($x < 100) {
   echo 'True.';
}
else {
   echo 'False.';
}

[dylan.mann]

Thanks. Got that, I just wanted to clarify that I had messed up what I was trying to say originally.