[machoolah]

Hello everyone,

I am trying to create a class with a list of a user-defined data type as its member. I get the error: ISO C++ forbids declaration of 'list' with no type. Could anyone tell me what I should change in the code to get it to work? (in util.h line 13)

Thanks!

Filename: main.cpp

#include<iostream>
#include<list>

#include "util.h"

using namespace std;

REFERENCE_SET ref_set;

int main(){

	REFERENCE_SET s;
	return 0;
}

Filename: util.h

#ifndef UTIL_H
#define UTIL_H

class ARRAY{
public:
	int ele[100];
	int size;		
	ARRAY();
};

class REFERENCE_SET{
public:
	list<ARRAY> perm;
	int size; 
	
	REFERENCE_SET();
};

#endif

Filename: util.cpp

#include "util.h"

ARRAY::ARRAY(){
	size = 0;
}


REFERENCE_SET::REFERENCE_SET(){
	size = 0;
}

This post has been edited by machoolah: 26 July 2011 - 05:17 PM

[GWatt]

It does not appear that you have included the list header in util.h. Since your class declaration is in util.h is uses list there.

[machoolah]

That doesn't solve the problem! I still get the same error. Can you tell me where exactly I should include the header?

[GWatt]

/*
 util,h
*/
#ifndef UTIL_H
#define UTIL_H

#include <list> // INCLUDE LIST HERE

class ARRAY{
public:
	int ele[100];
	int size;		
	ARRAY();
};

class REFERENCE_SET{
public:
	list<ARRAY> perm;
	int size; 
	
	REFERENCE_SET();
};

#endif

[machoolah]

I still get the same error! =(

[GWatt]

You also need to specify the namespace containing list, sinc it's not in the global namespace.

std::list<TYPE> obj;

[#define]

You probably want the std namespace as well.

std::list<ARRAY> perm;

[jimblumberg]

The list class is in the namespace std, so you need to use the scope resolution operator for the std namespace, std::list<ARRAY> perm;

Jim

[machoolah]

WOW, thanks for all your replies. This works perfectly now! =)