[runtime error]

ok i have a question (shocking i know).

i have a list of numbers and i have to print from a specified row and column to a specified row and column.
easy as pie if i could use a multi-dimensional array. But i cant.so i need to know what goes into the element part of the array.

void text_display (int array[ ], int nr, int nc, int start_row, int start_column,
                            int end_row, int end_column)
{
int r,c;
r=start_row;
while (r<=end_row)
{
c=start_column;
while(c<=end_column)
{
cout<<array[what goes in here?];
c++;
}
r++;
cout<<endl;
}
}

nr and nc is the amount of rows and columns i have to work with. the rest is self explanatory.

Thanks.

[malkiri]

I think I know what you're asking...
If the data would look like this if you used a multi-dimensional array:
1 2 3 4
5 6 7 8
9 10 11 12
but instead looks like this in your single dim. array:
1 2 3 4 5 6 7 8 9 10 11 12
All you would need to do to find the index of the element at row row and column column is:

index = (column - 1) + (row - 1)*row_length

where row_length is the length of the rows.
(this is based on the assumption that row & column are indexes starting at 1. if they start at 0, then drop the " - 1" part.)

-Malkiri

[malkiri]

Now someone post the code to find the row and column in the multi-dimensional array, given the index in the single dimensional array and the row and column lengths. :)

[Null and Void]

int FirstIndex  = (int)(Index / Width);
int SecondIndex =      (Index % Width);

Math is your friend. So is properly used integer truncation.

[runtime error]

woohoo i knew you guys would pull through for me. Thanks!
:biggrin:

[malkiri]

I should have said, "Now someone other than Null and Void..." :)