[assert(C)]

Hello,


I need to a make a function in C which will keep looping onlt if the input is numbers or + I want the input to be numbers cause I want to do something with them. Please help


Regards,

This is IN C

[darek9576]

Well, there is a isdigit() function but it will only return true if input is 0, 1, 2,3,4,5,6,7,8 or 9. Otherwise false. But you can play with it and find out more.

[assert(C)]

Please Help Not sure what to do I have tried manythings but I cant seem to work it out

[darek9576]

I have this example in C++. However i am not testing whether its a number cuz im assuming the user will input the number.

Spoiler

#include <iostream>

using namespace std;

void printArray(int* a, int size)
{
	for(int i=0; i < size; i++)
	{
		cout << *a << endl;
		a++;
	}
}

int main()
{
	int number;
	cout << "How many numbers do you want to store?:  ";
	cin >> number;

	int *a = new int[number];
	int *b = a;
	
	for(int i=0; i < number; i ++)
	{
		cout << "provide the number: ";
		cin >> *a;
		a++;
	}

	printArray(b,number);

	cin.ignore();
	cin.get();

	return 0;
}

This post has been edited by darek9576: 23 September 2011 - 04:09 AM

[assert(C)]

but I want to still loop even if + is entered so it should loop still.

[Ghost344]

So basically the programs has to DO the input WHILE the input EQUALS a digit OR a plus sign?

[assert(C)]

Yes Yes Yes Yes Yes but how do it I have tried many things HELP HELP HELP

BUT YES THATS WHAT IT HAS TO DO

[assert(C)]

Please help

[Ghost344]

You could post all the methods you tried so far, could save some time.

[darek9576]

This does not store anywhere your entries but you could use a vector for it however, i dont know vectors so you need to look it up and it stops also when user presses +. Add an OR clause at the end of the loop.
Good luck.

Spoiler

int main()
{
	
	char input;

	

	


	do{
		cout << "Type in something" << endl;
		cin >> input;
		cout << input << endl;

	}while( isdigit(input));

	cout << "Finishing the program" << endl;



	cin.ignore();
	cin.get();

	return 0;
}

This post has been edited by darek9576: 23 September 2011 - 04:47 AM

[assert(C)]

NO NO it should continue to loop even when a plus sign is added or digit anything else it should stop. What I did was I talk the input as string and decalred flag then if strcmp(input,"+") is true flag is ture and if number then true but does not work. I have tried many ways. I just want to basically loop if a number or plus sign is entered.

P.S. EVERYONE THANKS ALOT FOR YOUR HELP I THINK I AM NEARLY THERE

[Aphex19]

The answer I gave in your other thread is pretty much all you need. Just put the code in a while loop and add some sort of boolean flag which can be used as the condition for your loop. It's very trivial to expand the code to do that.

[assert(C)]

But man I think aphex19 correct me if I am wrong you are taking one signle input from user like for example 12+1212121231 which correct but I want to scanf values in a loop and then check them. If they contain a number or plus sign if they do the loop continues else loop is terminated.

[darek9576]

assert©, on 23 September 2011 - 04:49 AM, said:

NO NO it should continue to loop even when a plus sign is added or digit anything else it should stop. What I did was I talk the input as string and decalred flag then if strcmp(input,"+") is true flag is ture and if number then true but does not work. I have tried many ways. I just want to basically loop if a number or plus sign is entered.

P.S. EVERYONE THANKS ALOT FOR YOUR HELP I THINK I AM NEARLY THERE

I know it should loop when + is entered and thats what i said in my post. Add one condition in my code and you are done. THen show us what you have produced.

[assert(C)]

I had to learnt C++ to try your code okay got it working for c++ but I need the same concept in C here is the code in C++ thanks man


[code]
int main()
{

char input;



do{
cout << "Type in something" << endl;
cin >> input;
cout << input << endl;

}while( isdigit(input) !! input=='+');

cout << "Finishing the program" << endl;



cin.ignore();
cin.get();

return 0;
}


Thanks works the only thing left is translating in C and also converting the character if number into a number