[Khalix]

Many companies use telephone numbers like 555-GET-FOOD so the number is easier for their customers to remember. On a standard telephone, the alphabetic letters are mapped to numbers in the following fashion:

A, B, and C = 2
D, E, and F = 3
G, H, and I = 4
J, K, and L = 5
M, N, and O = 6
P, Q, R, and S = 7
T, U, and V = 8
W, X, Y, and Z = 0

Write a program that asks the user to enter a 10-character telephone number in the format XXX-XXX-XXXX. The program should display the telephone number with any alphabetic characters that appeared in the original translated to their numeric equivalent. For example, if the user enters 555-GET-GOOD the application should display 555-438-3663.

import javax.swing.JOptionPane;

public class Telephone
{
     public static void main(String[] args)
     {
	String input;
	int phoneNum; //to hold telephone number
	int [] letter;   						//  List variables
	int [] number;							//  that you will be using
												//  in the program.





	/*****************************************************************/ 		
	   //------------------Input the Data---------------------------
	   
	input = JOptionPane.showInputDialog("Enter a XXX-XXX-XXXX Telephone Number with Letters or Numbers: ");
	
	phoneNum = input();

I know that my code is wrong. I am having trouble figuring out how to get the input from the JOptionPane to be able to use an array. I think an array is the best was to do this, but I am also unsure if I should be using one array for letter and another for numbers. I just want to make sure that I am on the right track, and a little help in the right direction getting from the JOptionPane to the array would be appreciated.

My problem is that every example I can find in my textbook and online uses the system.out.prntln method and I am struggling to use the JOptionPane method...which is required in the assignment.

[g00se]

The only reason to use an array is as a lookup table. A Map is another possibility. Read the characters separately with String.charAt(n)

[macosxnerd101]

I agree with g00se here. I would use a Map<Character, Character>. So:

Map<Character, Character> map = new HashMap<Character, Character>();
map.put('A', '2');
map.put('B', '2');

char translate = map.get('B'); //returns '2'

That should get you a good idea of how to proceed.

This post has been edited by macosxnerd101: 30 October 2011 - 06:14 PM
Reason for edit:: Corrected illegal syntax

[g00se]

Yes. Digits and dashes can have identity mappings, then the whole output can be derived from the Map (cleaner)

[pbl]

don't forget

map.put('-', '-');

[Khalix]

I like the idea of this,and I have started putting it together. However I am still pretty new at this, and I can't find anything in my textbook about mapping. Is there a certain variable or class I need to import for the code that you listed to work?

I get the overall idea of using mapping but there is something I am not doing because I keep getting errors.

import javax.swing.JOptionPane;
import java.util.HashMap;
import java.util.Collection;

public class Telephone
{
     public static void main(String[] args)
     {
	String input;
	String number; //to hold telephone number   		
	HashMap hashMap = new HashMap();	
	
	
		/*****************************************************************/ 		
	   //------------------Input the Data---------------------------
	   	
	Map<Character, Character> map = new Map<Character, Character>();
	map.put('A', '2');
	map.put('B', '2');
	map.put('C', '2');
	map.put('D', '3');
	map.put('E', '3');
	map.put('F', '3'); 

[pbl]

which errors ?

[Khalix]

----jGRASP exec: javac -g Telephone.java

Telephone.java:36: error: cannot find symbol
Map<Character, Character> map = new Map<Character, Character>();
^
symbol: class Map
location: class Telephone
Telephone.java:36: error: cannot find symbol
Map<Character, Character> map = new Map<Character, Character>();
^
symbol: class Map
location: class Telephone
2 errors

----jGRASP wedge2: exit code for process is 1.
----jGRASP: operation complete.

[pbl]

Actually Map is an Interface use

Hashtable<Character, Character> map = new Hashtable<Character, Character>();

[g00se]

Hashtable is really a legacy class and in this case has the unneeded property of being synchronized

[Khalix]

I'm still getting the same error. Here is the code exactly as I have so far. And I apologize, like I said this Map is new to me. It seems very handy, if only I could get it to work

import javax.swing.JOptionPane;
import java.util.HashMap;
import java.util.Collection;

public class Telephone
{
     public static void main(String[] args)
     {
	String input;
	String number;   		
	HashMap hashMap = new HashMap();	
	
	
			   	
			{
			Hashtable<Character, Character> map = new Hashtable<Character, Character>();			map.put('A', '2');
			map.put('B', '2');
			map.put('C', '2');
			map.put('D', '3');
			map.put('E', '3');
			map.put('F', '3');
			map.put('G', '4');
			map.put('H', '4');
			map.put('I', '4');
			map.put('J', '5');
			map.put('K', '5');
			map.put('L', '5');
			map.put('M', '6');
			map.put('N', '6');
			map.put('O', '6');
			map.put('P', '7');
			map.put('Q', '7');
			map.put('R', '7');
			map.put('S', '7');
			map.put('T', '8');
			map.put('U', '8');
			map.put('V', '8');
			map.put('W', '9');
			map.put('X', '9');
			map.put('Y', '9');
			map.put('Z', '9');
			map.put('-', '-'); 
			}
			
		input = JOptionPane.showInputDialog("Enter a XXX-XXX-XXXX telephone number with letters or numbers: ");
	

[macosxnerd101]

Make sure you import HashTable from the java.util package.

[Khalix]

using HashMap as opposed to HashTable seemed to fix it. Unless I am wrong and that is something else it ran with no errors when changing it to Map

[macosxnerd101]

macosxnerd101, on 30 October 2011 - 08:08 PM, said:

I agree with g00se here. I would use a Map<Character, Character>. So:

Map<Character, Character> map = new HashMap<Character, Character>();
map.put('A', '2');
map.put('B', '2');

char translate = map.get('B'); //returns '2'

That should get you a good idea of how to proceed.

I had some illegal, and misleading syntax in my previous example that I corrected a few minutes back. I'm sorry for my misleading example. Anyways, just to point out the corrected syntax.

And glad you found a solution!

[Khalix]

macosxnerd101, on 30 October 2011 - 06:27 PM, said:

macosxnerd101, on 30 October 2011 - 08:08 PM, said:

I agree with g00se here. I would use a Map<Character, Character>. So:

Map<Character, Character> map = new HashMap<Character, Character>();
map.put('A', '2');
map.put('B', '2');

char translate = map.get('B'); //returns '2'

That should get you a good idea of how to proceed.

I had some illegal, and misleading syntax in my previous example that I corrected a few minutes back. I'm sorry for my misleading example. Anyways, just to point out the corrected syntax.

And glad you found a solution!

And thank you for the help! So now once I list the

char translate = map.get('B');

lines will it pull that from the input and translate it? Or is there something else that I need to add other than that?

How do I run the input through the map and output in a JOption pane? I guess is the question I'm asking