[chica911]

this is what i have so far. It compiles but the out put is always Total of arrayName elements: 0. please help me thank you

	// Find the total result of 10 numbers
	
	public class SumArray 
   {
      public static void main(String args[])   
      {
         int[] arrayName;
			arrayName = new int [10];
			int total = 0;
					  
			
		  // add each element's value to total
           	for (int counter = 0; counter <arrayName.length; counter++)
   	      total= arrayName[counter]; 
				System.out.printf("Total of arrayName elements:" + " " + total); 
      
      }  // end main
   }  // end of class InitArray2 

[Ryano121]

Well you haven't given the values of the array elements any other values. Therefore the default value - zero - will be used. Essentially at the moment you are adding up ten lots of zero.

You will probably want to have another loop that gives values to the array elements, like -

for(int i = 0; i < arrayName.length; i++)
{
    arrayName[i] = i;
}

Which will give you an array containing the following values -

0,1,2,3,4,5,6,7,8,9

[chica911]

i tried that but now it only prints 9 and i dont think thats the total of the 10 numbers.

i tried that but now it only prints 9 and i dont think thats the total of the 10 numbers.

[AMZDeCoder]

My Solution:
1) You should assign some values to your array.
2) The statement should be outside your for loop,

System.out.printf("Total of arrayName elements:" + " " + total); 

3) You should do the following, the total should be initialized to zero and all elements should be successively added to it.

total += arrayName[counter];

Hope this helps.

[jon.kiparsky]

Pretend that this is totally new code to you:

arrayName[counter] = 42
total= arrayName[counter];
System.out.printf("Total of arrayName elements:" + " " + total);

What would you expect this code to print?

This post has been edited by jon.kiparsky: 07 November 2011 - 08:57 AM

[chica911]

Thank you, moving that statement outside my for loop fixed the problem. it works great!