[freshman_prog]

how can i find a number from an unorderd array.

[NickDMax]

Since the array is unordered the only way to find a particular entry is to go looking for it one by one.

for(int i=0; i<ArrayMax; i++)
{
	if (array[i]==number) {/* found it */ break; }
}

This is the big fall back to an unordered array.

BTW: try to name your posts more discriptivly.

This post has been edited by NickDMax: 24 March 2007 - 10:02 AM

[freshman_prog]

Thanks for reply sir but i m still facing problem
plz see my code and make it corect
waiting 4 ur reply
Naushad Qamar
student 1st year (CS)

#include <iostream>
#include <conio>

int main()

{
int a[5],i,t;
cout<<"enter ur numbers";
for(i=0;i<5;i++)
cin>>a[i];
for(i=0;i<5;i++)
cout<<a[i];
cout<<"enter number which u want to search";
cin>>t;
for(i=0;i<5;i++)
if (a[i]==t)

break;
cout<<"present";

cout<<"absent";
getch();
}

[PennyBoki]

If you want the position to be printed

for(i=0;i<5;i++)
if (a[i]==t) cout<<"The number was at  "<<i<<"position";

[NickDMax]

#include <iostream>
#include <conio>
using namespace std;

int main()

{
	//You should always use LOTS of comments
	//The comments will help you understand your programs
	//They will also aid the teacher in giving partial-credit if the
	//   program does not work.
	
	//Either give variables discriptive names, or list them out
	//  and add a comment discribing what they do.
	int a[5]; //Array to hold numbers.
	int i; //Used to loop though array.
	int t; //The number to search for.
	int found; //used to tell us if the number is found
	
	cout<<"Please enter your numbers: ";
	
	//Althoug the brackets are not required in for-loops and if-statments
	//  using them will greatly aid in program clarity and can save you from
	//  hard to find logic errors.
	for(i = 0; i < 5; i++)
	{
		cin >> a[i];
	}
	
	for(i=0;i<5;i++)
	{
		cout << "a[" << i << "] = " << a[i] << " ";
	}
	
	cout<<"\nenter number which you want to search for: ";
	cin>>t;
	
	//Here I used a technique I like to call flagging.
	//   The found variable (called a flag) will tell us if we actually found
	//   the number we were looking for. 0 == false, and non-zero == true
	found = 0; //assume we will not find it... (i.e. assume false)
	for(i=0; i < 5; i++)
	{
		if (a[i]==t)
		{
			found = i+1; //we DID find it!!! (set to true)
			//note i+1 is so that if i=0 found will still be >0
			break;
		}
	}
	
	//Now we check the status of our flag and see what we find.
	if (found)  //remeber in C++ nonzero is true so this is the same as "if (found != 0)"
	{
		cout<<"\nNumber found at position: " << found - 1 << "\n";
	} else
	{
		cout<<"That number is not is the array!\n";
	}
	
	//Lets not leave the teacher wondering if the program locked up.
	cout << "Press any key to continue..." << endl; //last cout should have endl to flush buffer (not really needed but good practice).
	getch();  //<---- not the best way to do this, though it works here.
	return 0; //Always DEFINE exit point.
}

[freshman_prog]

Thankyou very much Sir u r not only solve my problem but also clear my misconceptions.
these days i m studying string having problem with that
like sum of two strings etc if u send me a small program which help me in understanding it i will really thankful to you.
your wellwisher , NAUSHAD QAMAR

[Amadeus]

As an addition to Nick's suggestion, one could also use the boolean data type as opposed to the integer type to indicate success. It can often be more intuitive.