[hiddenghost]

I was using a regex sub replace that got assigned to a list in a for loop.

When the replace got assigned to the list it got converted to a tuple inside the list and a number got added as a second item in each tuple.

For example:

['thing1', 'thing2', 'thing3'] # would be converted to

[('thing1', 1), ('thing2', 1), ('thing3', 1)]

# so basically this
things = ['thing1', 'thing2', 'thing3']
i = 0
while i < len(things)
    thingies.append(re.sub('thing', 'a thing', things[i]))
    i += 1
print "".join(thingies) # shows error because [('thing1', 1), ('thing2', 1), ('thing3', 1)]

The code above is just a quick summary of what's going on.

I just want to know how those tuples with ones are being added, and how to prevent it if there is a way.
Whatcha think?

Unless this is normal.

This post has been edited by hiddenghost: 25 November 2011 - 10:04 PM

[cupidvogel]

I cannot see any reason why should your output come like this, except that you might have used re.subn inadvertently in place of re.sub. The former returns a tuple consisting of the new string and the number of non-overlapping occurrences that have been replaced. In your case, it is 1 for each value in things array, so each element should return something like ('a thing1',1).

[hiddenghost]

cupidvogel, on 26 November 2011 - 03:17 PM, said:

I cannot see any reason why should your output come like this, except that you might have used re.subn inadvertently in place of re.sub. The former returns a tuple consisting of the new string and the number of non-overlapping occurrences that have been replaced. In your case, it is 1 for each value in things array, so each element should return something like ('a thing1',1).

I think you might be right. I am going to check my code and see if i did use subn.