[mgrex]

So I almost got through the end of the chapter without a program error, but now it seems the following problem may be program/compiler related.

The programs runs and displays the result it's supposed to. But then a different pop up from microsft's visual c++ 2010 comes up. I have attached an image as well.



Source code

// This program provides a simple iterator demonstration.
#include <iostream> 
#include <vector>			// Include the vector header 
using namespace std;

int main() 
{ 
	int count;				// Loop counter 
	
	// Define a vector object. 
	vector<int> vect; 

	// Define an iterator object. 
	vector<int>::iterator iter;

	// Use push back to push values into the vector. 
	for (count = 0; count < 10; count++) 
		vect.push_back(count);	//vect.push_back(count+1); will do 1 to 19, rather than 0 to 9

	// Step the iterator through the vector, and use 
	// it to display the vector's contents. 
	cout << "Here are the values in vect: "; 
	for (iter = vect.begin(); iter < vect.end(); iter++) 
	{ 
		cout << *iter << " "; 
	} 

	// Step the iterator through the vector backwards. 
	cout << "\nand here they are backwards: "; 
	for (iter = vect.end() - 1; iter >= vect.begin(); iter--) 
	{ 
		cout << *iter << " "; 
	} 
	cout << endl;

	system("pause");
	return 0;
} 

Attached image(s)

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This post has been edited by mgrex: 06 March 2012 - 05:37 PM

[alias120]

I can find no reason that this should fail from the perspective of the STL and Standard Library. .begin and .end return bidirectional iterators, so this issue must be from VS itself. I'll keep looking into it.

[jjl]

Be careful what relational operator you use when comparing iterators. Use the != operator when comparing your iterator to the front or to the end.


i.e. this

for (iter = vect.begin(); iter < vect.end(); iter++) 

should be this

for (iter = vect.begin(); iter != vect.end(); iter++) 

[mgrex]

Unfortunately, doing that resulted in the same error.

[jjl]

You need to fix the operator in the other for loop as well

[mgrex]

Awesome, that did the trick. Thanks.