1 Replies - 491 Views - Last Post: 28 March 2012 - 02:52 PM Rate Topic: -----

#1 ktsirig  Icon User is offline

  • D.I.C Head

Reputation: 0
  • View blog
  • Posts: 94
  • Joined: 14-September 05

PHP pagination problem

Posted 28 March 2012 - 02:50 PM

Hi guys,

well I'm trying to formulate pagination view of my results from a Mysql query in my database. The thing is that the query is not known beforehand, since the user of the database can enter several search terms in text fields of the webpage (text_search.php) and when he hits the "Submit" button, the new page (retrieve_text.php) looks about which text fields have been filled and appends the values in the mysql query like this:

$text_query = ...... WHERE [user-defined conditions]



Everything is OK until now. But I wanted to show the results more clear to the user, since it can have e.g 600 results so it's not so good to view them in a loooooooooong page. So I tried to paginate them.

Now comes the problem: the first page looks Ok, and brings only 25 results, which I want to be the limit of results to show per page. BUT, when I click on the "Next button", I see nothing. The reason? In pages 2,3...N, the $text_query is empty since there are no values submitted through the $_POST variable..., So, in the 1st page, if I print the SQL query I have something like that:

SELECT DISTINCT protein.protein_id, protein.protein_name FROM protein LEFT JOIN protein_reference ON protein_reference.prot_ref_protein_id = protein.protein_id LEFT JOIN reference ON reference.reference_id = protein_reference.prot_ref_reference_id LEFT JOIN families ON protein.protein_families_id = families.families_id WHERE protein.protein_name LIKE '%protein%' ORDER BY protein.protein_id LIMIT 0, 25



while in the 2nd page for example I get:

SELECT DISTINCT protein.protein_id, protein.protein_name, protein.protein_seq_len, protein.protein_organism, protein_ncbi FROM protein LEFT JOIN protein_reference ON protein_reference.prot_ref_protein_id = protein.protein_id LEFT JOIN reference ON reference.reference_id = protein_reference.prot_ref_reference_id LEFT JOIN families ON protein.protein_families_id = families.families_id WHERE ORDER BY protein.protein_id LIMIT 25, 25



The reason is, as I wrote before, that the where clause in the sql statement is written on-the-fly so the sql search is dynamic and not static. If it was static, like

SELECT * from protein WHERE name LIKE '%protein%';



things would be straight-forward.

What can I do? Should/Could I somehow "send" the sql query from page to page? I suppose this is BAD practice, but I don't really know how to proceed...

Is This A Good Question/Topic? 0
  • +

Replies To: PHP pagination problem

#2 JackOfAllTrades  Icon User is offline

  • Saucy!
  • member icon

Reputation: 6058
  • View blog
  • Posts: 23,496
  • Joined: 23-August 08

Re: PHP pagination problem

Posted 28 March 2012 - 02:52 PM

Save the POST variables in the session?
Was This Post Helpful? 0
  • +
  • -

Page 1 of 1