[suyed]

#include<stdio.h>
#include<conio.h>
int main()
{
int A[5],B[5],C[10];
int i,k,j;
int flag;
clrscr();

printf("enter 5 elements of A");
for(i=0;i<5;i++)
{
	scanf("%d",&A[i]);
}
printf("\nenter elements of B");
for(j=0;j<5;j++)
{
	scanf("%d",&B[j]);
}

k=0;
for(i=0	;i<5;i++)
{
	C[k]=A[i];
	k++;
}
for(j=0;j<5;j++)
{
	flag=0;
	for(i=0;i<5;i++)
	{
		if(B[j]==A[i])
		{
			flag=1;
			break;
		}
	}
	if(flag==0)
	{
		C[k]=B[j];
		k++;
	}
}
for(i=0;i<k;i++)
printf("a union b is %d\n",C[k]);
return 0;
}

[Skydiver]

So what is your question?

[suyed]

suyed, on 06 July 2012 - 11:47 PM, said:

sir,i m a beginner and has jus started learning c
i cant get a correct output for dis code.. i m getin some garbage values..
please help me out..

#include<stdio.h>
#include<conio.h>
int main()
{
int A[5],B[5],C[10];
int i,k,j;
int flag;
clrscr();

printf("enter 5 elements of A");
for(i=0;i<5;i++)
{
	scanf("%d",&A[i]);
}
printf("\nenter elements of B");
for(j=0;j<5;j++)
{
	scanf("%d",&B[j]);
}

k=0;
for(i=0	;i<5;i++)
{
	C[k]=A[i];
	k++;
}
for(j=0;j<5;j++)
{
	flag=0;
	for(i=0;i<5;i++)
	{
		if(B[j]==A[i])
		{
			flag=1;
			break;
		}
	}
	if(flag==0)
	{
		C[k]=B[j];
		k++;
	}
}
for(i=0;i<k;i++)
printf("a union b is %d\n",C[k]);
return 0;
}

Skydiver, on 06 July 2012 - 11:48 PM, said:

So what is your question? i cant get the correct
output

Skydiver, on 06 July 2012 - 11:48 PM, said:

i cant get correct output..

sorry i m using dis web for the first so getting difficult to use it bt i will learn it slowly...

[Skydiver]

Take a closer look at your line 45. The last entry you put it C was at C[k-1], so C[k] is uninitialized. But then, why are you looping on i, but displaying C[k]?

This post has been edited by Skydiver: 07 July 2012 - 12:01 AM

[suyed]

sir i replaced k by i in my line 45 and now i got my desired output..
i just did on a trial and error basis i actually didnot understand what actualy has been happening over that last for loop ..
can u explain me

This post has been edited by jimblumberg: 07 July 2012 - 05:28 AM
Reason for edit:: Removed unecessary quote tags

[Skydiver]

Let me bounce the question back to you: Explain what your code does in lines 11-14 and 16-19. Why are you doing those loops? Where is the input going into in each iteration?

Now, go back and look at your lines 44-45. How is this similar or different to lines 11-14, 16-19?

[suyed]

compiler stores a integer values in a variable i which is again required to be of integer type.
i then increaments its value by 1 and checks the condition whether it is less than 5, if it holds true, it agains goes inside the loop and performs the statements till 1<5 ie 1=4.
when i=5 it does nt go inside the loop instead it performs the next statement after the for loop.

This post has been edited by jimblumberg: 07 July 2012 - 05:29 AM
Reason for edit:: Removed unecessary quote tags

[aresh]

First of all, please stop quoting and then changing the contents. It is irritating. And if you didn't understand the logic, how did you make it ?? Strange.

[suyed]

aresh, on 07 July 2012 - 01:17 PM, said:

i kno d logic and i m new to c so i m not very clear wid all d fundas of c and its programing..
u must be master in c but i m not and so i hav joined dis ..
dis i my first day and a very first topic so pls,,,
if u dont wanna clr my doubts its fine bt dont try to act oversmart wid me..

[aresh]

suyed, on 07 July 2012 - 12:47 PM, said:

i just did on a trial and error basis i actually didnot understand what actualy has been happening over that last for loop

As far as I am concerned, this means that you did not understand the logic.

[jimblumberg]

suyed, on 07 July 2012 - 10:40 AM, said:

i kno d logic and i m new to c so i m not very clear wid all d fundas of c and its programing..
u must be master in c but i m not and so i hav joined dis ..
dis i my first day and a very first topic so pls,,,
if u dont wanna clr my doubts its fine bt dont try to act oversmart wid me..

Since the OP doesn't seem to want to behave I'm going to close this topic.

Jim