[EmiT FliX]

mark = int(raw_input("Mark:"))
if mark < 50:
    print "Grade = F"
if mark >= 50 < 64:
    print "Grade = P"
if mark >= 65 < 74:
    print "Grade = CR"
if mark >= 75 < 84:
    print "Grade = D"
if mark >= 85 < 100:
    print "Grade = GOD DAMN BOI!!!!"

This doesn't print out right
say this happens
Mark: 66
this will print out as
Grade = P
Grade = CR

Now I have learnt that python is something where you throw every bit of logic you know away...

Anyways why is this printing wrong and how can it be fixed

[alexr1090]

Your logic is good. Python wants you to write it like this

if mark >=50 and mark < 64:

though.

[EmiT FliX]

mark = int(raw_input("Mark:"))
if mark < 50:
    print "Grade = F"
else:
    if mark >= 50 and mark <= 65:
        print "Grade = D"

    if mark >= 65 and mark <= 75:
        print "Grade = H"
else:
            if mark >= 75 and mark <= 85:
                print "Grade = HD"

Now all I get is a response back from the first ELSE

[alexr1090]

change the first else to elif and get rid of a tab below the last else

[EmiT FliX]

Syntax error on the elif

[alexr1090]

oh yeah sorry I didn't look close enough. There has to be a statement after an elif. So basically

mark = int(raw_input("Mark:"))
if mark < 50:
    print "Grade = F"
elif mark >= 50 and mark <= 65:
    print "Grade = D"

elif mark >= 65 and mark <= 75:
    print "Grade = H"
elif mark >= 75 and mark <= 85:
    print "Grade = HD"

So it's if mark <50: do this and go to past the last elif statement (in this case the end of the program). If mark isn't <50 but is >=50 and <=65 print grade d. Otherwise if mark is >=65 and <=75 print grade=H. Otherwise if mark >=76 and mark <=85 print grade = hd. Making sense now?

[EmiT FliX]

Yes, that makes perfect sense and thanks for the code, saved alot of time, I'm just reading up on elif

[alexr1090]

no problem glad I could help.

[baavgai]

Now that you have the syntax, note that you don't two value test.

if mark < 50:
    print "Grade = F"
# here, you already know mark >= 50 
# because you know that "not mark < 50"
# you can take advantage of this
elif mark >= 50 and mark <= 65:

e.g.

if mark < 50:
	print "Grade = F"
elif mark < 64:
	print "Grade = P"
elif mark < 74:
	print "Grade = CR"
elif mark < 84:
	print "Grade = D"
elif mark < 100:
	print "Grade = GOD DAMN BOI!!!!"
else:
	# if we make it here, mark >=100
	print "No one is that good."

[EmiT FliX]

Yes, I was having trouble with this for a very long time atleast 3 or 4 hours , but it was dumbed down enough for me to understand, and tomorrow, help others having the problem, though I do like your code usage

[atraub]

alexr1090, on 13 August 2012 - 12:26 AM, said:

Your logic is good. Python wants you to write it like this

if mark >=50 and mark < 64:

though.

I do want to point this out while I'm here. if mark >= 50 < 64 is wrong but not as wrong as you think. this condition checks to see if mark is greater than or equal to 50 and if 50 is less than 64. The latter will always equate to true, when will 50 ever be greater than 64? This syntax is correct and does what you had in mind

if 50 <= mark < 64

For the narrow set of situations where it's appropriate, this syntax is much cleaner... if 50 is less than or equal to mark and mark is less than 64. Granted, baagvais approach is better, but I wanted you to be aware that this syntax exists.

This post has been edited by atraub: 13 August 2012 - 04:28 PM