[NunoSantos]

Hi guys...i have one doubt, can, anybody, give me an hand?
i have one dictionary that contain keys. These keys are taxonomics levels but they are unsorted.
How can i sort this taxonomic levels by these order: domain, superkingdom, kingdom, phylum, class,order, family, genus, species?

for key in dtResult:
            print "\nPresenting results for: " + str(key).upper()
            for key2 in dtResult[key]:
                print "\t" + str(key2) + ": " +str(dtResult[key][key2]) 

that code give me what i want but not in the order that i specified before.
ideas?
thanks
Nuno

This post has been edited by macosxnerd101: 12 September 2012 - 08:45 AM
Reason for edit:: Fixed code tags

[Tayacan]

A dictionary is unsorted by definition - the keys are the indices. What you can do is extract a list of keys, sort it, and then look up the items in the dictionary in that order. Look here.

[atraub]

Tayacan, on 12 September 2012 - 01:17 PM, said:

A dictionary is unsorted by definition - the keys are the indices. What you can do is extract a list of keys, sort it, and then look up the items in the dictionary in that order. Look here.

Well said.

[charles314]

d1=
d1={'a domain':111, 'b superkingdom': 222, 'c kingdom': 333, 'd phylum': 444, 'e class': 555, 'f order': 666, 'g family': 777, 'h genus': 888, 'i species': 999}

<br/>
<br/>

sorted(d1)
['a domain', 'b superkingdom', 'c kingdom', 'd phylum', 'e class', 'f order', 'g family', 'h genus', 'i species']

[charles314]

Sorry about the post. Not sure what happened, and, no way to edit I guess.

[Tayacan]

charles314, on 13 September 2012 - 09:12 PM, said:

d1=
d1={'a domain':111, 'b superkingdom': 222, 'c kingdom': 333, 'd phylum': 444, 'e class': 555, 'f order': 666, 'g family': 777, 'h genus': 888, 'i species': 999}

<br/>
<br/>

sorted(d1)
['a domain', 'b superkingdom', 'c kingdom', 'd phylum', 'e class', 'f order', 'g family', 'h genus', 'i species']

Notice how you only get the keys this way - you'd then use this nice, sorted list of keys to look up stuff in the right order.

[charles314]

sorted(d1.values()),sorted(d1.keys())
([111, 222, 333, 444, 555, 666, 777, 888, 999], ['a domain', 'b superkingdom', 'c kingdom', 'd phylum', 'e class', 'f order', 'g family', 'h genus', 'i species'])

Definitely. Here is another way to do it. Many others.

[charles314]

You could print them like this:

for key, value in d1.iteritems():
	print key, value

[atraub]

Here's a quick and simple example:

>>> d1 = {1:"1",5:"5",2:"2"}
>>> for key in sorted(d1.keys()):
	print(d1[key])

	
1
2
5

[NunoSantos]

thanks guys...i've created an array with the order that i want and then i used a for cicle like that

vectTaxonOrder = ['domain', 'superkingdom' ,'kingdom', 'phylum', 'class','subclass', 'order', 'suborder','family', 'subfamily','tribe','subtribe','genus', 'species','subspecies' ]
        for i in range (0, len(vectTaxonOrder)):
            if dtResult.has_key(vectTaxonOrder[i]):
                print "\nPresenting results for lever: "+str(vectTaxonOrder[i]).upper() + ": "
                for key in dtResult[vectTaxonOrder[i]]:
                    print "\t"+str(key)+": " + str(dtResult[vectTaxonOrder[i]][key])

thanks to all of you

This post has been edited by Simown: 17 September 2012 - 08:37 AM
Reason for edit:: Fixed code tags