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It should only succed if there is two consecutive values in the list.
I would make member2 and then try work it in append.
member2a(X,L). append([],X,X). append(_,[X,X|_],X) :- member2a(X,[]).
2 Replies - 422 Views - Last Post: 30 September 2012 - 12:59 PM
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Prolog: Express the predicate member2 using the predicate append only
Posted 30 September 2012 - 11:31 AM
Im not quite sure how to do this. (Recursion is not allowed)
It should only succed if there is two consecutive values in the list.
I would make member2 and then try work it in append.
It should only succed if there is two consecutive values in the list.
I would make member2 and then try work it in append.
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Re: Prolog: Express the predicate member2 using the predicate append only
Posted 30 September 2012 - 12:35 PM
Like this ofcourse
member2a(X,[X,X|_]). member2a(X,[_|T]) :- append(_,[X,X|_],X), append(_,[T|_],X).
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