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#1 snowingCa  Icon User is offline

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multi-thread for computing sum of numbers

Posted 04 October 2012 - 02:45 PM

I have this program in C++, it count sum of one thread,I don't know how to make a sum of multi thread with a program divide the numbers from 1 to N into T groups of consecutive numbers.
For example, it has a 4 group, with N = 15, G = 4. TG1 = (1,2,3,4), G2 = (5,6,7,8), G3 = (9,10,11,12) and G4 = (13,14,15).
The output is ./sum 15 4
Thread 1 (1,4)
Thread 2 (5,8)
Thread 3 (9,12)
Thread 4 (13, 15)
Sum (1,15) = 120
Can anyone help me, please!.
Thanks in advance

--------------------------------------------


#include <pthread.h>
#include <iostream>
#include <cstdlib>

using namespace std;

// The adder thread that will add the number from 1 to n
void *adder(void * number);

// The sum variable that will be updated by all threads
unsigned long sum;

int main(int argc, char *argv[])
{
if (argc != 2) {
cerr << "Usage: sum <integer value>" << endl;
exit(1);
}

unsigned long number = atol(argv[1]);
if (number < 0) {
cerr << "Argument " << number << " must be non-negative." << endl;
exit(1);
}

pthread_t tid; // the thread identifierier
pthread_attr_t attr; // set of attributes for the thread

// get the default attributes
pthread_attr_init(&attr);

// create the thread
pthread_create(&tid,&attr,adder,(void *) number);

// Wait for the thread to exit
pthread_join(tid,NULL);

cout << "Sum(" << 1 << ", " << number << ") = " << sum << endl;

return 0;
}

// Add the numbers from 1 to n
void *adder(void * number)
{
cout << "Thread ID = " << pthread_self() << endl;

unsigned long num = (unsigned long) number;
for (int i = 1; i <= num; i++)
{
sum += i;
}

pthread_exit(0);
}

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#2 jimblumberg  Icon User is offline

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Re: multi-thread for computing sum of numbers

Posted 04 October 2012 - 02:50 PM

Duplicate topic. Topic closed.

Jim
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