Hi. I have to resolve some homework question. By using a series of instruction pop(), push(), peek() and empty(, i need to carry out some instruction.
 For example, set x to the 2nd element of stack, leaving stack without top element so it will be pop(s) and x=peek(s).
 Then I have example 2: instruction  set x to third element of stack, leaving stackk unchanged.
What you think about this sequence: pop(s),pop(s), x=peek(s), push(s), push(s), pop(s), pop(s), push(s),push(s)?
Set elements of stack java
Page 1 of 13 Replies  464 Views  Last Post: 07 October 2012  10:25 AM
Replies To: Set elements of stack java
#2
Re: Set elements of stack java
Posted 05 October 2012  09:47 AM
Wait. How are we suppose to know what element we are on? We don't know the size of the stack.
Also. The peek and pop methods have no arguments so is S suppose to be the stack?
Also. The peek and pop methods have no arguments so is S suppose to be the stack?
#3
Re: Set elements of stack java
Posted 05 October 2012  04:54 PM
hi. but the answer for first example is correct for 100% becuase its a teacher example. I did not get the size of the stack. Also it doesnt say in which position x actually is. For these exercises I can use the stack 1 nd stack 2, push(s,d) pushes element 'd' onto the stack. there is one more example to solve: 'set x to the bottom, leave stack empty'.
pop(s),pop(s), x=peek(s), push(s,d), push(s,e), pop(s), pop(s), push(s,e),push(s,d)? is this answer better for second example?
pop(s),pop(s), x=peek(s), push(s,d), push(s,e), pop(s), pop(s), push(s,e),push(s,d)? is this answer better for second example?
pop(s),pop(s), x=peek(s), push(s,d), push(s,e), pop(s), pop(s), push(s,e),push(s,d)? is this answer better for second example?
pop(s),pop(s), x=peek(s), push(s,d), push(s,e), pop(s), pop(s), push(s,e),push(s,d)? is this answer better for second example?
#4
Re: Set elements of stack java
Posted 07 October 2012  10:25 AM
Hi. If someone can close this topic? I have found some explanation. Dnt need ny more answer. thanks anyway
Page 1 of 1
