[Salem_c]

aychdogg, on 09 October 2012 - 04:23 PM, said:

See this was what I wanted all along and I had a bit of idea about this but there was some error.

You know, posting your latest effort, errors and all, is what we're all about.

So what is YOUR latest effort?

[aychdogg]

Well guys ofcourse I did mention I am new to this so I'm trying to learn more and more stuff. From what I got from Salem_c's code was that he used "(perline+1)*lines" so that we can get all the asterisks at once e.g 15. Then he used "[i%(perline+1)==perline]" later to seperate 5 asterisks and get the remainder. I hope I'm correct on that?

[aychdogg]

no2pencil, on 09 October 2012 - 10:45 AM, said:

The op clearly doesn't understand the exercise or how to code it. You guys are basically doing this for him. That's why he didn't answer yes. He doesn't know.

Sir, I respect you replying to my post and all and I did mention I'm new to this so I think you need to spare me that constant nag. Ofcourse I don't know all this otherwise I wouldn't have asked for a barely 5,6 lines of code. You guys are pros so you know stuff in details while I'm here to learn. I didn't get to reply to Jim's post #22 because I saw Salem_c
s post later. I know what he was talking about though. Salem_c's code actually helped me and I tried learning whatever concept he has used. I have googled each concept to learn it so by the time i get judged on my level of programming skills I'll have enough knowledge on this and i don't have to worry about my instructor being totally daft.

[Salem_c]

> Well guys ofcourse I did mention I am new to this so I'm trying to learn more and more stuff.
Well you see, learning how to program is rather different than learning magic tricks.

Your post #3 was perfectly adequate solution for anyone learning C. In fact, it's perfectly adequate in almost every context you can imagine - if you just take the requirement to print *** in a square, and ignore the completely stupid limitation of "use one loop".

And like all magic tricks, it's obvious when you see it, and rather pointless when you understand it. Ultimately, it doesn't help you solve any other problem.

Now imagine you were to give your code to someone else (exceedingly likely in professional programming). But now the requirement has changed to put a + in each corner. With your code at post #3, it's a relative simple task that anybody could achieve.

With my cryptic 'fun' code, you're basically screwed for figuring out how to do it. The most obvious (and sane) thing to do would be to delete it and do it properly with an obvious nested loop.

[Skydiver]

aychdogg, on 10 October 2012 - 04:14 AM, said:

From what I got from Salem_c's code was that he used "(perline+1)*lines" so that we can get all the asterisks at once e.g 15.

Try again. perline == 5, lines == 3. So (perline+1)*lines == (5+1)*3 == 6*3 == 18. 18 != 15.

aychdogg, on 10 October 2012 - 04:14 AM, said:

Then he used "[i%(perline+1)==perline]" later to seperate 5 asterisks and get the remainder. I hope I'm correct on that?

If that is used for getting the remainder then the following should print out 2:

int i = 7;
int perline = 5;
printf("%d", i%(perline+1)==perline);

But somehow it prints out 0.

[jimblumberg]

The purpose of my question in post #22 was to ascertain the actual requirements. If you can print a variable instead of a constant character, it is much easier to complete this task using only one loop. By adding an if or if/else statement to the loop it is very easy to print your "box" using a single loop and single printf(). And I agree with Salem_c, using his cryptic code is not the way to accomplish this objective.

Jim

[aychdogg]

alright. thanks.

[MasterUvPuppetz]

um.. can i ask for a c++ equivalent for this exercise?

Thanks in advance,