[xnoviice]

First I don't expect the question to be handed to me I just need a push.

Okay so right now what I am trying to do is enter minutes and then seconds and the seconds are to be 60 seconds or below (obviously) So the code I am trying right now is a bit like this

 

int min_total = 0;
int sec_total = 0;
const int minute = 60;
int seconds_to_min;
     
     cin >> min >> sec ;
     min_total = min_total + min;
     sec_total = sec_total + sec;
    sec_total = minute % sec_total;
    cout << min << sec;

is there any help that could be given? It would mean a lot if there was!

This post has been edited by xnoviice: 07 October 2012 - 07:54 PM

[jimblumberg]

Help for what? You need to ask a question.

Jim

[xnoviice]

Oh! sorry! um! okay well the question is when the seconds goes up to 60 how do I get it to be added into minuets and seconds go back down to 0??

[jimblumberg]

How would you do it using pencil and paper? In other words, how many seconds are in a minute? If you have 60 of something how to you get zero?

Jim

[xnoviice]

Ok. Thanks! that's the little push I needed! I now have it working! I am going to put this here if anyone ever had the same question for reference! Thanks again!

const int minute = 60;

      cin >> min >> sec ;
     min_total = min_total + min;
     sec_total = sec_total + sec;
     min_total = min_total + sec_total / minute;     
     sec_total = sec_total % minute;

[jimblumberg]

What happens if minutes is larger than 60? I would also recommend the use of parentheses in your second min_total calculation. While not actually required they will make your intent much clearer. Also don't forget about the second "shortcut" form.

min_total = min_total + (sec_total / minute);  
// OR
min_total += sec_total / minute;

Jim

[xnoviice]

Well for the program I am doing hours does not have to be involved for it is for the 80 minuets a CD can hold. also thank you for the reminder of cleaning up my code! I was just to excited finding it out to remember!