[PSCA]

Ive been playing around with the turtle in blueJ/java
i want it to make a semicircle so i created a method with the following code

public void drawSemiCircle(int radius)
    {
        this.forward(5);
        this.turn(20);
        this.forward(5);
        this.turn(20);
        this.forward(5);
        this.turn(20);
        this.forward(5);
        this.turn(20);
        this.forward(5);
        this.turn(20);
        this.forward(5);
        this.turn(20);
        this.forward(5);
        this.turn(20);
        this.forward(5);
        this.turn(20);
        this.forward(5);
        this.turn(20);
        this.forward(5);
        this.turn(20);
        this.forward(5);
        this.turn(20);
        this.forward(5);
    }

its too long and repetative, is there anyway to make it shorter?
new at this

[Ryano121]

Look into looping

while

for

[PSCA]

Ryano121, on 10 October 2012 - 09:13 AM, said:

Look into looping

while

for

So i would do this instead?

    public static void main(String[] args)
{
int count = 1;         
while(count<12);
}

}
}

[pbl]

public void drawSemiCircle(int radius) {
 
    for(int i = 0; i < 12; i++) {
        this.forward(5);
        this.turn(20);
    }
}

[PSCA]

pbl, on 10 October 2012 - 01:39 PM, said:

public void drawSemiCircle(int radius) {
 
    for(int i = 0; i < 12; i++) {
        this.forward(5);
        this.turn(20);
    }
}

So i could do this with any repetitive code?
I have some that it repeats twice then it changes then repeats the first two twice again, i wouldnt be able to use looping for that would i ?

thank you for the help on my original question:)!

[pbl]

There is surely a way.... depends on your exact pattern
you can have nested loops too so it depends

[PSCA]

pbl, on 10 October 2012 - 01:49 PM, said:

There is surely a way.... depends on your exact pattern
you can have nested loops too so it depends

[quote]
public void drawAStar(int Length)
{
this.turn(90);
this.forward(Length);
this.turn(155);
this.forward(Length);
this.turn(270);
this.forward(Length);
this.turn(155);
this.forward(Length);
this.turn(280);
this.forward(Length);
this.turn(155);
this.forward(Length);
this.turn(270);
this.forward(Length);
this.turn(155);
this.forward(Length);
this.turn(286);
this.forward(Length);
this.turn(150);
this.forward(Length);



}
[/code]

id assume this one would be difficult to do because nothing is competative other than the sideLength portion

[rfs02]

This looks like the solution to a homework problem, but here it goes anyway...

Put the turns in an array: int[] turns = { 90, 155, ...}

Then create a loop that picks up the angle from the turns array and then moves forward by length.