[Dus]

Hi

I couldn't understand how to do a program using two functions!! However, I must use at least two functions in this project

[Write a function that computes future investment value at a given interest rate for a specified number of years. The future investment is determined using the following formula:

Accumulative Value =
investmentAmount * (1 + MonthlyInterestRate) NumberofYears*12]

 
#include <iostream>
#include<math.h>
#include<iomanip>
using namespace std;

int InvesAmount, years, i, futureValue;
float annualRate,monthlyRate;

float futureV()
{
    for (i=1;i<=years;i++)
        futureValue=InvesAmount*pow((1+monthlyRate),(i*12));
    cout<<"Years"<<setw(16)<<"Future Value\n";
    cout<<i      <<setw(16)<<futureValue;
}

int main()
{
    cout<<"Enter your investment amount";
    cin>>InvesAmount;
    cout<< "How much is the interest rate?";
    cin>>annualRate;
    monthlyRate=(annualRate/100)/12;
    cout<<"For how long you want to invest?";
    cin>>years;
    cout<<"Your future inestment values are  ";
    futureV;
}

Errors:
Control reaches end of non-function
Expression result unused
No Debug Session

[To repeat, your program should at least consist of two functions, the main function and a function that calculates the balance]

Please I want to understand how I do two functions, I didn't find good tutorials in this subject

thanks

[CTphpnwb]

This should stop the immediate error:

    cout<<"Your future inestment values are  " <<  futureV();

but you're not passing anything to the function, so it's still not going to do what you want.

Read up on functions.

[JackOfAllTrades]

There are also my function tutorials, linked in my signature.

[Dus]

CTphpnwb, on 12 October 2012 - 09:15 AM, said:

This should stop the immediate error:

    cout<<"Your future inestment values are  " <<  futureV();

but you're not passing anything to the function, so it's still not going to do what you want.

Read up on functions.

Thank u for ur help and I've read the article, but couldn't get how it works in sophisticated functions.
Could you please explain what do you mean that I am not passing anything?
when I write the function name( futureV() ), is it suppose to call the function?

JackOfAllTrades, on 12 October 2012 - 09:24 AM, said:

There are also my function tutorials, linked in my signature.

Thank you I'll check them

[raghav.naganathan]

Basically a function is written like this.

return_type functionName(parameters if any)
{
//code
//return_value if return_type is not 'void'
}

So according to this,your futureV() function is supposed to return a floating point value so it would do you a lot good if you could use a 'return' statement instead of a cout so that your function works correctly.

regards,
Raghav

This post has been edited by raghav.naganathan: 12 October 2012 - 12:00 PM

[Dus]

raghav.naganathan, on 12 October 2012 - 11:59 AM, said:

Basically a function is written like this.

return_type functionName(parameters if any)
{
//code
//return_value if return_type is not 'void'
}

So according to this,your futureV() function is supposed to return a floating point value so it would do you a lot good if you could use a 'return' statement instead of a cout so that your function works correctly.

regards,
Raghav

Could you please explain how i use return instead of cout?

Thank u

the code

#include <iostream>
#include<math.h>
#include<iomanip>
using namespace std;

int InvesAmount, years, i, futureValue;
float annualRate,monthlyRate;

float futureV()
{
    for (i=1;i<=years;i++)
    { futureValue=InvesAmount*pow((1+monthlyRate),(i*12));
        cout<<i      <<setw(16)<<futureValue;}
}

int main()
{
    cout<<"How much is your investment amount?";
    cin>>InvesAmount;
    cout<< "How much is the annual interest rate?";
    cin>>annualRate;
    monthlyRate=(annualRate/100)/12;
    cout<<"How many years you want to invest?";
    cin>>years;
    cout<<"Your future inestment values are\n"<<"Years"<<setw(40)<<"    Future Value\n"<<futureV();
    
} 

[raghav.naganathan]

Dus, on 13 October 2012 - 12:36 AM, said:

raghav.naganathan, on 12 October 2012 - 11:59 AM, said:

Basically a function is written like this.

return_type functionName(parameters if any)
{
//code
//return_value if return_type is not 'void'
}

So according to this,your futureV() function is supposed to return a floating point value so it would do you a lot good if you could use a 'return' statement instead of a cout so that your function works correctly.

regards,
Raghav

Could you please explain how i use return instead of cout?

Thank u

Let me illustrate that to you with this example

float sum()
{
float num1=1.0,num2=2.0,sum_float;
sum_float=num1+num2;
return sum_float;
}

Try along the same lines. You can use cout as well but make sure you provide a return statement after you do the cout.

regards,
Raghav

[jimblumberg]

@raghav.naganathan
Please find an indentation style you like and use it consistently. Especially when providing answers using your own code. In my opinion proper indentation is a mandatory item for proper program structure.

float sum()
{
   float num1 = 1.0, num2 = 2.0, sum_float;
   sum_float = num1 + num2;
   return sum_float;
}

Jim

This post has been edited by jimblumberg: 12 October 2012 - 12:26 PM

[raghav.naganathan]

jimblumberg, on 13 October 2012 - 12:54 AM, said:

@raghav.naganathan
Please find an indentation style you like and use it consistently. Especially when providing answers using your own code. In my opinion proper indentation is a mandatory item for proper program structure.

float sum()
{
   float num1 = 1.0, num2 = 2.0, sum_float;
   sum_float = num1 + num2;
   return sum_float;
}

Jim

Sure Jim, thank you for that suggestion. Will keep that in mind when I am posting next time

regards,
Raghav