[adityamithal]

Month=1
x = 100
v = 5000
z = (annualInterestRate)/12 
while(balance >= 1):
   balance = v 
   while(Month <= 12):
        balance = (balance - x) * (1 + z)
        Month+=1
   x+=10    
print('Lowest Payment: ' + str(x))

The above code is not working
i am trying to find the amount which is min required to pay each moth so that the credit amount at the end of 12 months should be 0 and the amount paid monthly should be fixed

[atraub]

Care to tell us what's wrong with it? Define "not working".

[adityamithal]

atraub, on 13 October 2012 - 07:40 AM, said:

Care to tell us what's wrong with it? Define "not working".

compiler is not showing any output
and says error reading code

[atraub]

We can not see your computer screen. Would you care to copy and paste the error into your reply so that we can be on the same page? If you do, please use code tags.

[adityamithal]

atraub, on 13 October 2012 - 08:42 AM, said:

We can not see your computer screen. Would you care to copy and paste the error into your reply so that we can be on the same page? If you do, please use code tags.

Month=1
x = 20
v = balance
z = (annualInterestRate)/12 
i=0
while(v >= 1):
   v = balance
   Month = 1
   for i in range(12):
       v = (v - x) * (1 + z)
       Month+=1
   x+=10


x-=10
print('Lowest Payment: ' + str(x))

The above code works fine but i have to make it through bisection search.
I don`t know where to start for it

[atraub]

do you know what bisection search is? can you describe how it works, step-by-step? Pretend I have no idea how it works.

[adityamithal]

atraub, on 14 October 2012 - 07:27 PM, said:

do you know what bisection search is? can you describe how it works, step-by-step? Pretend I have no idea how it works.

step 1:
we assume 2 points 1) - lower bound
2) - Upper bound

lower bound has the lowest possible value
upper bound has the largest possible value

step 2:

we add both of them and divide by 2

step 3:

now if the possible value is in the middle ie what we get after dividing or whether it is below or above it

step 4:

if the value is above the answer then we make the answer the lower bound and the upper bound remains the same or vise-verse

step 5:

repeat these steps until found

[atraub]

Very good, now of these steps, which ones are you unsure how to translate into code?

EDIT:
I don't understand 3 and 4... you say we do something if a certain condition is true... but you never say what we're suppose to do.

This post has been edited by atraub: 15 October 2012 - 08:00 PM