So I am trying to use a while loop to show everything from 1 to 55 using (n * (n + 1)) / 2 equation.

while n <=55:

# while loop for (n * (n + 1)) / 2 to get up to 55

Page 1 of 1## 7 Replies - 850 Views - Last Post: 16 October 2012 - 12:27 PM

##
**Replies To:** while loop for (n * (n + 1)) / 2 to get up to 55

### #2

## Re: while loop for (n * (n + 1)) / 2 to get up to 55

Posted 16 October 2012 - 11:15 AM

Ok I am not sure what had happened but it didn't let me finish so.

Not sure. I am a beginner in my second week.

n = 1 while n <=55: print n n +=1 (n * (n + 1)) / 2

Not sure. I am a beginner in my second week.

This post has been edited by **Simown**: 16 October 2012 - 11:21 AM

Reason for edit:: code tags!

### #3

## Re: while loop for (n * (n + 1)) / 2 to get up to 55

Posted 16 October 2012 - 11:16 AM

First of all, you are not assigning n to your equation on the last line. Also, you are incrementing n and I don't think you need to, getting to 55 will be done by the equation. Try:

Does that help?

n = 1 while n <=55: print n n = (n * (n + 1)) / 2

Does that help?

This post has been edited by **Simown**: 16 October 2012 - 11:21 AM

### #4

## Re: while loop for (n * (n + 1)) / 2 to get up to 55

Posted 16 October 2012 - 11:35 AM

With the way you did it it does not add 1 each time. Timeout my program with a ton of 1 1 1 1 1 1 1 1 1 1 1 etc.

Actually the darn thing worked after I posted. Not sure why it wasn't before.

Ok so If I were to incorporate it into a def. This one is kicking my butt.

Actually the darn thing worked after I posted. Not sure why it wasn't before.

Ok so If I were to incorporate it into a def. This one is kicking my butt.

from test import testEqual n = 1 def sumTo(n <=55): print n n +=1 (n * (n + 1)) / 2

### #5

## Re: while loop for (n * (n + 1)) / 2 to get up to 55

Posted 16 October 2012 - 11:40 AM

I didn't know it worked. I was just revising your code. I assumed it did.

What are you looking for in a function? I guess you want to set the upper limit

What are you looking for in a function? I guess you want to set the upper limit

def sumTo(x): n = 1 while(n <= x): print n n = (n * (n+1)) / 2

### #6

## Re: while loop for (n * (n + 1)) / 2 to get up to 55

Posted 16 October 2012 - 11:45 AM

This is what the online book is telling me.

Write a fruitful function sumTo(n) that returns the sum of all integer numbers up to and including n.

So sumTo(10) would be 1+2+3...+10 which would return the value 55. Use the equation (n * (n + 1)) / 2.

Write a fruitful function sumTo(n) that returns the sum of all integer numbers up to and including n.

So sumTo(10) would be 1+2+3...+10 which would return the value 55. Use the equation (n * (n + 1)) / 2.

### #7

## Re: while loop for (n * (n + 1)) / 2 to get up to 55

Posted 16 October 2012 - 12:14 PM

That's not what you have then, that's basically just applying a single function to the parameter:

def sumTo(n): print (n * (n+1)) / 2 ... >> sumTo(10) 55

### #8

## Re: while loop for (n * (n + 1)) / 2 to get up to 55

Posted 16 October 2012 - 12:27 PM

Oh my, So I was trying to make it harder than it actually was.

Thank you.

Thank you.

Page 1 of 1