int counter = 1;
int a=1;
double product=0;
while (counter<=20){
if(a%2!=0){
product += a*(a+2);
}
a++;
}
System.out.println(product);
7 Replies - 164 Views - Last Post: 06 December 2012 - 08:13 PM
#1
Getting the product of the first 20 odd integers.
Posted 06 December 2012 - 06:57 PM
It compiles, but not result appears.
Replies To: Getting the product of the first 20 odd integers.
#2
Re: Getting the product of the first 20 odd integers.
Posted 06 December 2012 - 07:04 PM
What result are you getting? Is it printing out a 0?
#3
Re: Getting the product of the first 20 odd integers.
Posted 06 December 2012 - 07:22 PM
#4
Re: Getting the product of the first 20 odd integers.
Posted 06 December 2012 - 07:25 PM
Ahh silly me. You have an infinte loop. Your counter variable is never incremented, therefor your while condition is never false. Try combining your counter and "a" into a single variable, and refactoring your code to use a for loop. It should be easier to read
#5
Re: Getting the product of the first 20 odd integers.
Posted 06 December 2012 - 07:43 PM
Argh not doing well with this.. I simply cannot figure out the correct formula for this.. What I got so far.. Guess I need a break =/
int product=1;
for (int counter =1;counter<=20;counter++){
if(counter%2!=0){
counter = counter*(counter+2);
product *= counter*(counter+2);
}
}
System.out.println(product);
#6
Re: Getting the product of the first 20 odd integers.
Posted 06 December 2012 - 07:45 PM
Don't modify your counter variable inside the if statement.
Your counter in this case goes from 1 to 20. If it's odd, calculate the product. You don't do any calculations with your counter variable.
Edit: With your calculation it's like this. 1*3*5*7... So keep your previous product, and multiply the new odd number. No need to do anything fancy.
Your counter in this case goes from 1 to 20. If it's odd, calculate the product. You don't do any calculations with your counter variable.
Edit: With your calculation it's like this. 1*3*5*7... So keep your previous product, and multiply the new odd number. No need to do anything fancy.
This post has been edited by nunc: 06 December 2012 - 07:47 PM
#7
Re: Getting the product of the first 20 odd integers.
Posted 06 December 2012 - 08:03 PM
Try this
public class Odd_20 {
public static void main(String...args){
int counter = 1,cnt=1;
int a=1;
double product=1;
int i=1;
while (counter<=20*2){
if(a%2!=0){
product *=a;
}
a++;counter++;
}
System.out.println(product);
}
}
This post has been edited by burakaltr: 06 December 2012 - 08:33 PM
#8
Re: Getting the product of the first 20 odd integers.
Posted 06 December 2012 - 08:13 PM
Or a fancier way of doing this
import java.text.NumberFormat;
public class Odd_20 {
static {
System.out.println("stat");
}
public static void main(String...args){
int counter = 1,cnt=1;
int a=1;
double product=1;
int i=1;
while (counter<=20*2){
if(a%2!=0){
product *=a;
}
a++;counter++;
}
NumberFormat form=NumberFormat.getIntegerInstance();
System.out.println(product+" = "+form.format(product));
}
}
This post has been edited by burakaltr: 06 December 2012 - 08:33 PM
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