increasing a number by a percentage
Page 1 of 114 Replies  464 Views  Last Post: 28 January 2013  04:27 AM
#1
increasing a number by a percentage
Posted 28 January 2013  02:02 AM
but you cant do that in java because it dosent take into account the remainder
any help is appreciated
Thanks dale
Replies To: increasing a number by a percentage
#2
Re: increasing a number by a percentage
Posted 28 January 2013  02:07 AM
#3
#4
Re: increasing a number by a percentage
Posted 28 January 2013  02:11 AM
regards,
Raghav
#5
Re: increasing a number by a percentage
Posted 28 January 2013  02:22 AM
20% increate on 495
thanks for the help by the way.
#6
Re: increasing a number by a percentage
Posted 28 January 2013  02:51 AM
regards,
Raghav
#7
Re: increasing a number by a percentage
Posted 28 January 2013  02:55 AM
#8
Re: increasing a number by a percentage
Posted 28 January 2013  03:32 AM
Could be used as follows:
int x = 0; //this will be used as your original number double result = (x / 100) * 120; //this number is 120% of x
#9
Re: increasing a number by a percentage
Posted 28 January 2013  03:35 AM
I don't understand what you mean about the remainder though, did you mean decimal?
Edit: To Flukeshot, that piece of code will have a problem with integer division. X will need to also be a double, or divide by '100.0'.
This post has been edited by Mylo: 28 January 2013  03:40 AM
#10
Re: increasing a number by a percentage
Posted 28 January 2013  03:54 AM
Quote
The alternative to
double result = (x / 100.0) * 120; // added .0
is
double result = x * 1.2;
which seems slightly more reliable. That is, we are not likely to forget the decimal point.
Added: The problem that we are avoiding is that if x is an integer value of 80 then performing x / 100 will use integer arithmetic, producing a value of 0  which when multiplied by 120 is still 0. Using x / 100.0 avoids this issue, as does multiplying by 1.2. 100.0 and 1.2 are both doubles, forcing Java to use floatingpoint arithmetic.
This post has been edited by andrewsw: 28 January 2013  04:09 AM
#11
Re: increasing a number by a percentage
Posted 28 January 2013  04:07 AM
public class MyClass { public static float getPercentFromAmount(int amount) {//As suggested by Andrew(in bold) return (float) (amount + (amount* [b]20/100.0[/b])); //here is where the type casting is taking place } public static void main(String args[]) { float a= getPercentFromAmount(100); System.out.print(+a); } }
Edit : Optimized some code and made the change suggested by andrewsw
regards,
Raghav
This post has been edited by raghav.naganathan: 28 January 2013  04:25 AM
#12
Re: increasing a number by a percentage
Posted 28 January 2013  04:16 AM
raghav.naganathan, on 28 January 2013  04:07 AM, said:
public class MyClass { public static float getPercentFromAmount(int amount) { return (float) ((float) amount + (float) (amount* 20/100)); //here is where the type casting is taking place } public static void main(String args[]) { float a= getPercentFromAmount(100); System.out.print(+a); } }
This has the same issue as the OP. If you run it and enter the value 4 it gives the result 4 rather than 4.8. You can either do:
(amount* 20/100.0) // or ((float) amount * 20/100)
This post has been edited by andrewsw: 28 January 2013  04:17 AM
#13
Re: increasing a number by a percentage
Posted 28 January 2013  04:21 AM
regards,
Raghav
#14
Re: increasing a number by a percentage
Posted 28 January 2013  04:24 AM
Else I don't see your problem
My suggestion was doing it like andrewsw has already shown
value = (int) (value * 1.2);
#15
Re: increasing a number by a percentage
Posted 28 January 2013  04:27 AM
