[Orochimaru]

How should I loop this num_check function to stop once I get an int?
I feel like a while loop is a better choice than using a for loop. But I can't figure out how to integrate the while loop for this situation. />/>

# http://www.dreamincode.net/forums/topic/186908-sanity-check-for-raw-input-being-integer/
# http://learnpythonthehardway.org/book/ex35.html

# http://learnpythonthehardway.org/book/ex48.html
# http://learnpythonthehardway.org/book/ex21.html


# number = (int(raw_input(" Enter a number: ")))

def convert_number(s):
    try:
        return int(s)
    except ValueError:
        return None
        #exit(5)


#num1 = convert_number('@')
#print "This is what function-except-ValueError returned: %r" % num1

#num2 = convert_number(-3.333)
#print "\nThis is what function returned: %r" % num2


number = raw_input(" Enter a number: ")
num3 = convert_number(number)
print "\n\tThis is what function returned: %r\n" % num3

[andrewsw]

It would be better if you made an attempt at this yourself, then we could help you with your code. Study this:

while True:
    number = input(" Enter a number: ")
    num3 = convert_number(number)
    if num3 is not None:
        print ("\n\tThis is what function returned: %r\n" % num3)
    else:
        break

[Orochimaru]

It worked thanks! />/>

def convert_number(s):
    try:
        return float(s)
    except ValueError:
        return None


#num1 = convert_number('@')
#print "This is what function-except-ValueError returned: %r" % num1

#num2 = convert_number(-3.333)
#print "\nThis is what function returned: %r" % num2


while True:
    number = raw_input(" Enter a number: ")
    num3 = convert_number(number)

    if num3 is None:
        print "\n\tThis is what function returned: %r\n" % num3
    else:
        break