[GregBrannon]

I don't see that error in what you've posted. What I do see is the use of type char that will not provide the results you're expecting. For example,

String numString = "12345";
int num = numString.charAt( 2 );

will not assign the value of 3 to num. It will instead assign the decimal ASCII value of the character '3' to num.

You might try something like:
int num1 = Integer.parseInt( "" + num.charAt(0) );

[louisianapadawan]

GregBrannon, on 10 March 2013 - 03:43 AM, said:

I don't see that error in what you've posted. What I do see is the use of type char that will not provide the results you're expecting. For example,

String numString = "12345";
int num = numString.charAt( 2 );

will not assign the value of 3 to num. It will instead assign the decimal ASCII value of the character '3' to num.

You might try something like:
int num1 = Integer.parseInt( "" + num.charAt(0) );

Thank you, that works. But I don't understand why. How does adding the "" + inside the parenthesis get it to read it as an int? Just curious. I'm trying to understand what I'm doing and not just "copy code to get an assignment done." I understand the ASCII part but I don't get how the "" + helps convert it to an int.

[macosxnerd101]

The Integer.parseInt() method accepts a String parameter. The String charAt(0) method returns a char, so the num.charAt(0) + "" concatenates the char with a String, to return a String. Thus, the Integer.parseInt() method now has a String parameter.

Alternatively, you could do:

int value = num.charAt(0) - '0';

Remember that chars have equivalent numerical values, and '0' (as a char) != 0 (as an int), so subtracting '0' from the char will return the appropriate int. So '2' - '0' == 2.

[louisianapadawan]

macosxnerd101, on 10 March 2013 - 11:56 AM, said:

The Integer.parseInt() method accepts a String parameter. The String charAt(0) method returns a char, so the num.charAt(0) + "" concatenates the char with a String, to return a String. Thus, the Integer.parseInt() method now has a String parameter.

Alternatively, you could do:

int value = num.charAt(0) - '0';

Remember that chars have equivalent numerical values, and '0' (as a char) != 0 (as an int), so subtracting '0' from the char will return the appropriate int. So '2' - '0' == 2.

So any char - 0 = the appropriate int ?

[macosxnerd101]

If you have the chars '0' through '9' and you subtract '0', you will get the appropriate int. Be advised that '0' != 0, so quotes matter. The ASCII table will tell you the int value of '0', as a char.

[louisianapadawan]

Thanks mac and everyone else!