[rustix]

How could I create a function to check whether a string (word or sentence) passed into an array have any repeating character and delete them?

This is what I've done so far:

#include <stdio.h>

/*
1) Enter in a string
2)String should be checked for repeating characters (call a function)
3)The repeating characters hould be deleted (within the function)
4)New modified string should be displayed (returned from the function to be printed in the main method)
*/

//check whether repeating strings are present
char no_repetitions(char str[]);

char no_repetitions(char str[])
{
	
}

//main method
main()
{
	static char string[] = "this is";
	printf ("Enter in a string : ");
	scanf ("%s", string);
	printf ("The entered words in : %s", string);
}

example of expected output

Quote

Enter a string : This string contains repeated characters
The string without repetition is : This trngcoaepd

I know it's not much at all but I really am a newbie and want to know could this be done? are regular expressions involved? is there a way to do this with out using reg expressions?

This post has been edited by rustix: 28 November 2007 - 11:31 AM

[Pontus]

gonna give u some pseudocode

create another array that will hold all the chars already found (array2)
start looping to all characters
if the current char is already in array2 delete it
else
add it to array2
end loop

now the code for the removal in an array

char *delete(char *inputarray,int wich,int sizeofarray)
{
 int b=0;
 char ret[sizeofarray-1];

 for(int a=0;a<sizeofarray-1;a++)
 {
  if(a!=wich)
  ret[a]=inputarray[b++];
 }
}

[rustix]

manhaeve5, on 28 Nov, 2007 - 02:50 PM, said:

now the code for the removal in an array

char *delete(char *inputarray,int wich,int sizeofarray)
{
 int b=0;
 char ret[sizeofarray-1];

 for(int a=0;a<sizeofarray-1;a++)
 {
  if(a!=wich)
  ret[a]=inputarray[b++];
 }
}

thanks i managed to do it but without the removal in an array part... i don't quite understand why you have that part..

[Pontus]

To remove characters in an array.