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it closes before i can see the out put i tried using
int yes;
cin >> yes;
but i still can see the result can any one help !!??
so here's the code and it closes right away
this is a Base conversion application
// basecnvtr.cpp : Defines the entry point for the console application.
//
/*
Base conversion functions
This code may be used freely in any project but I can't guarantee that there aren't any bugs
(If you use this then no credit to the creator is required, but I would appreciate an email)
How it works:
Example 1: Converting 20 (dec) to binary...
20/2 = 10 (+ remainder 0)
10/2 = 5 (+ remainder 0)
5/2 = 2 (+ remainder 1)
2/2 = 1 (+ remainder 0)
1/2 = 0 (+ remainder 1)
The complete number (00101) needs to be reversed, so it equals 10100
Example 2: Converting 4C9 (hex - base 16) to decimal
First, find the place value and face value of each digit:
Digit : 4 C 9
Face value : 4 12 9 (..note: Hex C means 12. A=10,B=11,C=12,D=13,E=14,F=15)
Place value: 256 16 1
Then multiply each face value by its place value and add all together:
(256*4)+(16*12)+9 = 1024+192+9 = 1225
Therefore, 4C9h = 1225d
http://www.insidereality.net
*/
#include "stdafx.h"
#include <stdlib.h>
#include <string.h>
#include <math.h>
#include <cmath>
#include <iostream>
using namespace std;
//Declarations:
//Takes a decimal number, converts it to base and stores the result in szString. Returns 1 on success or 0 on failure
int DecToBase(int,long,char*);
//Takes a number in any base and converts it to decimal.
//Number is a pointer to a string containing the value to convert (a string to allow for A-Z).
//Base is the base that number is in (e.g.16, if it is Hex)
int BaseToDec(char*,int);
//Returns position of a character in a string
int GetIndex(char *,char);
//Symbols used to display a number correctly
//Numbers over base 10 use letters to represent values over and equal to 10
//You should be able to increase the max no. of bases by adding other symbols
//Remember a string needs 1 extra space for null character
char symbols[37] = "0123456789ABCDEFGHIJKLMNoPQRSTUVWXYZ";
const int MAX_BASE = 36; //Highest base allowed (make sure there are enough symbols first!)
//
int main(int argc, char* argv[])
{
char number[256] = "";
cout << "Base conversion functions. \n\n";
//DecToBase samples
cout << "Examples...\n\n";
DecToBase(2,10,number);
cout << "10dec to binary (base 2): " << number << endl;
DecToBase(8,25,number);
cout << "25dec to octal (base 8): " << number << endl;
DecToBase(3,49,number);
cout << "240dec to base 36 (hexatridecimal?): " << number << endl;
DecToBase(16,28,number);
cout << "28dec to hexadecimal (base 16): " << number << endl;
//I don't know why I wasted time working this one out... but 998453 spells LEET in base 36
DecToBase(36,998453,number);
cout << "998453dec to base 36: " << number << endl << endl;
//BaseToDec samples
cout << "4C9hex to decimal: " << BaseToDec("4C9",16) << endl;
cout << "1760octal to decimal: " << BaseToDec("1760",8) << endl;
cout << "1101011101bin to decimal: " << BaseToDec("1101011101",2) << endl << endl;
//User input sample
int iInput = 0,iBase = 2, iSrcBase = 10;
cout << "Try another conversion...\nEnter a number in any base between 2 and 36 (must be integer): ";
cin >> number;
cout << "Enter a base to convert from: ";
cin >> iSrcBase;
cout << "Enter a base between 2 and 36 to convert to: ";
cin >> iBase;
//If the source base is not 10, convert it to 10 first
if(iSrcBase!=10)
iInput = BaseToDec(number,iSrcBase);
else
iInput = atoi(number);
//If source base is not 10, and the destination base is, it is not nessecery to run DecToBase as the number
//Has already been found in base 10
if(iSrcBase!=10&&iBase==10)
{
cout << number << " in base " << iSrcBase << " = " << iInput << " in base " << iBase << endl << endl;
}
else
{
if(DecToBase(iBase,iInput,number))
cout << iInput << " in base " << iSrcBase << " = " << number << " in base " << iBase << endl << endl;
else
cout << "Error: Base was out of bounds... (must be between 2 and 36)\n\n";
}
return 0;
}
int DecToBase(int base, long iDec, char* szString)
{
//Check base is between 2 and 36
if(base<2||base>MAX_BASE)
return 0; //Failed
//If input is 0, output is 0
if(iDec==0){
strcpy(szString,"0");
return 1;
}
int count = 0;
char chResult[256] = "";
char* pChResult = chResult;
while(iDec > 0 && count++<256)
{
*pChResult = symbols[iDec % base];
pChResult++;
iDec = iDec/base; //iDec = itself divided by base
}
strcpy(chResult,_strrev(chResult));
strcpy(szString,chResult);
return 1;
}
int BaseToDec(char* number, int base)
{
if(base<2||base>MAX_BASE)
return 0; //Failed
int NumLength = strlen(number);
int PlaceValue, total = 0;
//Work out the place value of the first digit (base^length-1)
PlaceValue = (int)pow((double)base,NumLength-1);
//For each digit, multiply by its place value and add to total
for(int i=0;i<NumLength;i++)
{
total += GetIndex(symbols,*number)*PlaceValue;
number++;
PlaceValue /= base; //Next digit's place value (previous/base)
}
return total;
}
//Finds the index of a particular character (if it exists) in an array. Returns last character on failure
//Used by BaseToDec to find face values
int GetIndex(char * pString, char search)
{
int index = 0;
while(*pString != (char)0) //Loop will finish at null character if no match is found
{
if(*pString==search)
break;
pString++;
index++;
}
return index;
int yes;
cin >> yes;
}
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