[MagiCarpet]

Hey guys, I was just wondering: If I wanted to ask a user for an integer input and then find the sum of the digits that were entered, would there be any way of going about doing that?

[Quazzle]

I'm a bit confused. are u asking for the program where the input is something like "23" and the output is "2+3" or the program where the input is "2,3" and the output is "2+3" ? both are easy enough. plz just tell me which one ur looking for.

[MagiCarpet]

Yeah, like if the user put in 44, then there would be a message that says "The sum of the digits is 8." ....something like that.

[KYA]

string response;
int total = 0;
cout << "Enter a number:";
cin >> response;
for(int  i = 0; i < response.size(); i++)
{
	 total += (int)response.at(i);
}

I haven't ran it though, the typecast may or may not be necessary.

[Quazzle]

ha! KYA beat me to it. well thanks anyway KYA. I think mine had a small mistake.

[MagiCarpet]

Actually, it's working beautifully on this end the way it is. Thank you very much.

[JackOfAllTrades]

Except that's C++, not C.

[KYA]

You could do the same thing with a char array.

I need to L2R though

[JackOfAllTrades]

Indeed you could, with only a couple of changes. I just wanted the OP to be aware, in the event the assignment was C-specific.

[MagiCarpet]

Yeah thats ok...I converted to to C no problem.

[cguru]

Well magiCarpet.i believe u should make use of '%' and '/' along with bitwise operators to shorten your code.

below is a code to calculate sum of digits :

#include<stdio.h>
#include<conio.h>
int main()
{
	int num=0,tot=0;
	printf("Enter the number:");
	scanf("%d",&num);
	while(num)
	{
	  tot = tot + (num%10);
	  num=num/10;
	}	
	printf("The sum of Number is %d\n",tot);
	getch();
	return 0;
}

Hope this is useful to u..

This post has been edited by cguru: 11 December 2008 - 10:11 PM