[ribena500]

Hi,
I need to add together the values of an array that i have created,
my code:

#include "stdafx.h"
#include <iostream>
using namespace std;

int main ()
{
int i=0;
float hours_run[3], cal[3];
for(i=0; i<3; i++)

{
cout << "\n\Hours Run " << (i+1) << ": ";
cin >> hours_run[i];

cout << "calaories burnt " << (i+1) << ":";
cin >> cal[i];


}

cin.ignore(); cin.ignore();

}

I NEED TO ADD ALL THE VALUES FOR THE HOURS RUN, FOR EG IF THE HOURS RUN ARE 2 ,4,6 THEN I NEED IT TO DISPLAY 12 HOURS RUN

PLEASE HELP

[Gloin]

Gosh.. And this has an intermediate tag..

[ribena500]

Gloin, on 13 Jan, 2009 - 04:20 AM, said:

Gosh.. And this has an intermediate tag..

I TAKE IT YOU CAN HELP ME.
PLEASE HELP

[Gloin]

What is it that you need to sum up? I'm guessing the calories, so just use a variable, initiate it to 0. Loop over the values you need to sum up and add every value to the sum one by one. It's not more difficult than that.

[ribena500]

Gloin, on 13 Jan, 2009 - 04:23 AM, said:

What is it that you need to sum up? I'm guessing the calories, so just use a variable, initiate it to 0. Loop over the values you need to sum up and add every value to the sum one by one. It's not more difficult than that.

IM NOT THAT EXPERIENCED, CAN YOU HELP WITH THE CODE? PLEASE

[Gloin]

Ex: Sum all the values in the array cal[3]

int sum = 0;
for (j = 0; j < 3; j++)
  sum = sum + cal[j];

What do you represent with the array called hours_run?

[ribena500]

Gloin, on 13 Jan, 2009 - 04:26 AM, said:

Ex: Sum all the values in the array cal[3]

int sum = 0;
for (j = 0; j < 3; j++)
  sum = sum + cal[j];

What do you represent with the array called hours_run?

THE NUMBER OF HOURS THAT THEY HAVE RUN,
I BASICALLY WANT IT TO SAY:

YOU 3 HAVE RUN A TOTAL OF x HOURS
AND BURNT A TOTAL OF x CALS

[Gloin]

You can turn off the caps.

Ok.. So I'm assuming the calories burnt is represented as constant values meaning that if person1 and person2 each run for one hour they burn equal amount of calories. However, you burn different amount of calories every hour so running two hours mean you burn cal[0] + cal[1] calories.

For every person you can calculate the total number of burnt calories by first checking the number of hours the ran, then sum that many values from the cal array.

sum = 0;
for (person = 0; person < 3; person++) {
  for (hour = 0; hour < hours_run[person]; hour++)
	sum = sum + cal[hour];
}

I don't think this is exactly what you wanted. I intentionally chose a different setup but the idea is the same. This is just so you get a feel of how you can do things and something to think about.

[ribena500]

Gloin, on 13 Jan, 2009 - 04:43 AM, said:

You can turn off the caps.

Ok.. So I'm assuming the calories burnt is represented as constant values meaning that if person1 and person2 each run for one hour they burn equal amount of calories. However, you burn different amount of calories every hour so running two hours mean you burn cal[0] + cal[1] calories.

For every person you can calculate the total number of burnt calories by first checking the number of hours the ran, then sum that many values from the cal array.

sum = 0;
for (person = 0; person < 3; person++) {
  for (hour = 0; hour < hours_run[person]; hour++)
	sum = sum + cal[hour];
}

I don't think this is exactly what you wanted. I intentionally chose a different setup but the idea is the same. This is just so you get a feel of how you can do things and something to think about.

#

Thank you,
When i use this code, i get something different.
for eg if i entered person 1 - 3 hours, person 2 - 2 hours and person 3 - 4 hours
I get
3
5
9
Can i just not get it straight to 9

[JackOfAllTrades]

PROTIP: You don't have to print a variable every time it changes.

[Gloin]

JackOfAllTrades, on 13 Jan, 2009 - 04:50 AM, said:

PROTIP: You don't have to print a variable every time it changes.

What he said..

[ribena500]

Gloin, on 13 Jan, 2009 - 04:56 AM, said:

JackOfAllTrades, on 13 Jan, 2009 - 04:50 AM, said:

PROTIP: You don't have to print a variable every time it changes.

What he said..

i dont want to print it, all i want to day is to give me on sum figure

[Gloin]

ribena500, on 13 Jan, 2009 - 04:47 AM, said:

Thank you,
When i use this code, i get something different.
for eg if i entered person 1 - 3 hours, person 2 - 2 hours and person 3 - 4 hours
I get
3
5
9
Can i just not get it straight to 9

In the above example it seems you only calculated the sum of the hours (or cal[i] = 1 for all i)

[ribena500]

ribena500, on 13 Jan, 2009 - 04:59 AM, said:

Gloin, on 13 Jan, 2009 - 04:56 AM, said:

JackOfAllTrades, on 13 Jan, 2009 - 04:50 AM, said:

PROTIP: You don't have to print a variable every time it changes.

What he said..

i dont want to print it, all i want to day is to give me on sum figure

All i want it to say is you have run 9 hours.
I dont want it to print everything,
I cant seem to make this happen thiough

[David W]

Since you are using C++ why not use a vector of structs like below ...

Shalom,
David
http://developers-he...index.php/topic,46.0.html

#include <iostream>
#include <vector>

using namespace std;

struct mylog
{
	float hrs;
	float kcals;
};

bool more()
{
	cout << "More (y/n) ? ";
	cin.sync();
	int reply=cin.get();
	cin.sync();
	return !(reply=='n' || reply=='N');
}

int main()
{
	vector < mylog > ml;
	mylog tmp;
	cout << "Enter data for hours and kcalories  ...\n";
	do
	{
		cout << "Enter hours : ";
		cin >> tmp.hrs;
		cout << "Enter kcals  : ";
		cin >> tmp.kcals;
		if( !cin.good() )
		{
			cout << "Bad data entered ... Enter numbers only\n";
			cin.clear();
			cin.sync();
			continue;
		}
		ml.push_back( tmp );
	}while( more() );
	
	float tot_hrs =0, tot_kcals=0;
	for( unsigned i=0; i<ml.size(); ++i) 
	{
		tot_hrs += ml[i].hrs;
		tot_kcals += ml[i].kcals;
	}
	cout << "\nTotal hours = " << tot_hrs
		 << "\nTotal kcals = " << tot_kcals
		 << "\n\nPress 'Enter' key to continue ... " << flush;
	
	cin.sync();
	cin.get();
}