[binarimon]

//Prof suggests I add an If statement to my existing While loop, but he didn't elaborate. would
//I replace the IF statement I have, or add another? The goal is to just get the response to say Goodbye
//when I type Exit or exit. Right now it responds the same as when I type in any string.
//I read the input, do the output, but maybe only then test for "exit"?
//Would I be better off with a While loop vs a Do While Loop?
//TOTALLY Confused.

/**
	 Homework assignment that prompts for user input
	 */
	import java.io.BufferedReader;
	import java.io.IOException;
	import java.io.InputStreamReader;

public class Homework1{

	public static void main(String[] args){
		BufferedReader dataIn = new BufferedReader(new
		InputStreamReader(System.in));

		String name ="";
		do
		{
			System.out.print("Hi, what's your name?");
			try{
				 name = dataIn.readLine();
				 if(!(name.compareToIgnoreCase("quit")==0));
				 System.out.println(name + " it's so nice to meet you");
				 				 
					 
				 }
				catch(IOException e)
				 { 
					  System.out.println("error");
				 }
		}while(!(name.compareToIgnoreCase("exit")==0));
		System.out.println("Goodbye!");
	}
}

This post has been edited by binarimon: 19 January 2009 - 05:09 PM

[Martyr2]

Yeah replace the if you have there, it isn't doing anything anyways because you terminated it with a semicolon. This In its place you want to put an if statement like ...

if (!name.compareToIgnoreCase("exit")) { 
    System.out.println(name + " it's so nice to meet you");
}

This will allow the user to type in "exit" which will be stored in "name" and then with an if statement you check if it is equal to "exit" and if it is, you bypass the print. If it is not equal to exit, then it will say "____ its so nice to meet you"

This post has been edited by Martyr2: 19 January 2009 - 05:24 PM

[binarimon]

Hi,

thanks for this- makes sense but I'm getting errors typing it in like this:

if (!name.compareToIgnoreCase("exit")) { 
    System.out.println(name + " it's so nice to meet you");
}

Says operator ! is undefined.

??

Martyr2, on 19 Jan, 2009 - 04:22 PM, said:

Yeah replace the if you have there, it isn't doing anything anyways because you terminated it with a semicolon. This In its place you want to put an if statement like ...

if (!name.compareToIgnoreCase("exit")) { 
    System.out.println(name + " it's so nice to meet you");
}

This will allow the user to type in "exit" which will be stored in "name" and then with an if statement you check if it is equal to "exit" and if it is, you bypass the print. If it is not equal to exit, then it will say "____ its so nice to meet you"

[mostyfriedman]

compareToIgnoreCase() returns an int
so

if (name.compareToIgnoreCase("exit") != 0) { 
	System.out.println(name + " it's so nice to meet you");
}

This post has been edited by mostyfriedman: 19 January 2009 - 05:48 PM

[binarimon]

ok, the operator error went away but when I run and input "Exit". I still get "Exit, it's so nice to meet you!" instead of just goodbye!


/bin

mostyfriedman, on 19 Jan, 2009 - 04:48 PM, said:

compareToIgnoreCase() returns an int
so

if (name.compareToIgnoreCase("exit") != 0) { 
	System.out.println(name + " it's so nice to meet you");
}

[mostyfriedman]

import java.io.*;
public class HomeWork{
public static void main(String[] args){
		BufferedReader dataIn = new BufferedReader(new
		InputStreamReader(System.in));

		String name ="";
		do
		{
			System.out.print("Hi, what's your name?");
			try{
				 name = dataIn.readLine();
				 if(!(name.compareToIgnoreCase("exit")==0))
				 System.out.println(name + " it's so nice to meet you");
				
								 
					 
				 }
				catch(IOException e)
				 {
					  System.out.println("error");
				 }
		}while(!(name.compareToIgnoreCase("exit")==0));
		System.out.println("Goodbye!");
	}
}

ok i tested it for you, you just had to remove the ; after the if statement and change the condition in the while loop..now when the user enters exit, the loop will terminate and goodbye will be printed

[binarimon]

Hi,

sorry, what do you mean "change the "condition" in the While Loop?

Just taking the ; out of causes an error.

/bin

mostyfriedman, on 19 Jan, 2009 - 05:07 PM, said:

import java.io.*;
public class HomeWork{
public static void main(String[] args){
		BufferedReader dataIn = new BufferedReader(new
		InputStreamReader(System.in));

		String name ="";
		do
		{
			System.out.print("Hi, what's your name?");
			try{
				 name = dataIn.readLine();
				 if(!(name.compareToIgnoreCase("exit")==0))
				 System.out.println(name + " it's so nice to meet you");
				
								 
					 
				 }
				catch(IOException e)
				 {
					  System.out.println("error");
				 }
		}while(!(name.compareToIgnoreCase("exit")==0));
		System.out.println("Goodbye!");
	}
}

ok i tested it for you, you just had to remove the ; after the if statement and change the condition in the while loop..now when the user enters exit, the loop will terminate and goodbye will be printed

[mostyfriedman]

sorry i meant that i changed the condition in the if statement and removed the ; that was after the if statement

if(!(name.compareToIgnoreCase("quit")==0));

changed it to

if(!(name.compareToIgnoreCase("exit")==0))

i did that to make things work

you shouldnt type a semicolon after if statements.

[binarimon]

Okay cool. But what else did you change to get rid of the response:
"exit, it's nice to meet you"
"Goodbye!"

When you type in the word "exit" on the command line?

When I type Exit or exit, it should just come back cleanly with "goodbye!"

mostyfriedman, on 19 Jan, 2009 - 07:13 PM, said:

sorry i meant that i changed the condition in the if statement and removed the ; that was after the if statement

if(!(name.compareToIgnoreCase("quit")==0));

changed it to

if(!(name.compareToIgnoreCase("exit")==0))

i did that to make things work

you shouldnt type a semicolon after if statements.

[binarimon]

GOT IT!!! Needed to use name.equalsIgnoreCase not compareto.

First homework assignment that prompts for user input
	 */
	import java.io.BufferedReader;
	import java.io.IOException;
	import java.io.InputStreamReader;

public class Homework1{

	public static void main(String[] args){
		BufferedReader dataIn = new BufferedReader(new
		InputStreamReader(System.in));

		String name ="";
		do
		{
			System.out.print("Hi, what's your name?");
			try{
				 name = dataIn.readLine();
				 if(!(name.equalsIgnoreCase("exit")))
				 System.out.println(name + " it's so nice to meet you");
				 				 
					 
				 }
				catch(IOException e)
				 { 
					  System.out.println("error");
				 }
		}while(!(name.equalsIgnoreCase("exit")));
		System.out.println("Goodbye!");
	}
}

//Thanks for all your help here. I still don't get it all, but this was all very encouraging.

*Edited to fic the [ code] [ /code] tags

This post has been edited by pbl: 19 January 2009 - 09:57 PM