[mahaldita]

create a program that will accept a number and display it in reversed form.Make an equation to come up the best output..using do while loop.

[David W]

If you search through the

Quote

snippets

here at DIC

or look here ...

http://www.dreaminco...wtopic85415.htm

you may get a jump start ... this time

Shalom,
David

[soroush]

mahaldita, on 8 Feb, 2009 - 11:28 PM, said:

create a program that will accept a number and display it in reversed form.Make an equation to come up the best output..using do while loop.

here it is!

#include<iostream>
using namespace std;
int main()
{
	int i =0;
	int arr[5];
	cout<<"Please input 5 integers:"<<endl;
	do
	{
		cin>>arr[i];
		i=i+1;
}while(i<5);
	cout<<"In reverse order: "<<endl;

	i = 4;
do
	{cout<<arr[i]<<endl;
	i=i-1;
	}while(i>=0);
system("pause");
return 0;
}

[mahaldita]

soroush, on 10 Feb, 2009 - 12:20 PM, said:

mahaldita, on 8 Feb, 2009 - 11:28 PM, said:

create a program that will accept a number and display it in reversed form.Make an equation to come up the best output..using do while loop.

here it is!

#include<iostream>
using namespace std;
int main()
{
	int i =0;
	int arr[5];
	cout<<"Please input 5 integers:"<<endl;
	do
	{
		cin>>arr[i];
		i=i+1;
}while(i<5);
	cout<<"In reverse order: "<<endl;

	i = 4;
do
	{cout<<arr[i]<<endl;
	i=i-1;
	}while(i>=0);
system("pause");
return 0;
}

thanks sorous...this will be a great help.:-)

[David W]

... but if you want to reverse the order of digits in one number ... try the following ...

Shalom,
David

int reverseNum(int number)
{
    int rev = 0;
    while(number) /* exit when number is zero */
    {
        rev = rev*10 + number%10;
        number /= 10;
    }                
    return rev;
}