I need at least 50 summations of the approximation.

The partial code I wrote is:

long double z;

long double n=1;

long double seq;

for (int i=1;i<100;i+=2)

{n*=i;pow(z,n)/n;seq=pow(z,n);cout<<seq;

This post has been edited by **anonymous90**: 28 March 2009 - 03:55 PM