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- 19-February 09
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- May 30 2013 06:56 AM
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Posted 30 May 2012U got me Wrong!!
I was ment that a is a number in char!
like im doing:
scanf("%c", a); a = '2'; printf("%d", a-48);
Posted 30 May 2012is it the same??
I dont know, we are not allowed to use enything with *.. tought those are pointers..
Posted 30 May 2012so if i want that a for example will be 2 i need to do:
and it will give me: 2..
Posted 30 May 2012i'll try to work on something new! thank u!
BTW i cant use pointers.. otherwise it would be much easier for me...
Posted 30 May 2012Yes I see...
so u think that this code isnt right at all??
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