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  1. In Topic: Mechanics maths problem, please help me

    Posted 7 Dec 2012

    Your visual is of great aid, but you are using it wrong!

    So you know that A + B = 100

    Remember that A and B is distance here.

    What is the distance after the runner stopped accelerating? S = V * T
    This translates into: B = v * 8.6

    What is the distance during acceleration? S = 2(u + v) / t
    This translates into: A = 2 (8,8 + v ) / 2 = 8,8 + v

    Putting it all together:
    100 = 8,8 + v + v*8,6

    => 91,2 = 9,6v
    => v = 91,2 / 9,6 = 9,5 m/s

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