marwaa's Profile User Rating: -----

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User is offline Aug 13 2014 08:57 PM
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  1. In Topic: i cant solve this problem .. mysql_fetch_array() expects parameter 1

    Posted 13 Aug 2014

    I doo that also
    But still not working. :(
  2. In Topic: i cant solve this problem .. mysql_fetch_array() expects parameter 1

    Posted 13 Aug 2014

    i do what you say
    but its still not working




    i cahnge my code from mysql_fetch_assoc to _fetch_array
    i put date between $from_date and $to_date
    i put if (!$result1)


    what i can do more?


    <head>  <title >   report
    </title> </head> 
    
    <?php 
    session_start();
    $tbl_name="test_mysql"; // Table name 
    
    $db=mysql_connect('localhost','root','');
    if (!$db)die ("failed connection");
    mysql_select_db("test",$db);
    extract($_POST);
      
     $subject=$_POST['subject'];
     $orderr=$_POST['orderr'];
     $send_to=$_POST['send_to'];  
     $distribution=$_POST['distribution'];   
      $distribution2=$_POST['distribution2'];    
     $order_status=$_POST['order_status'];    
     $from_date=$_POST['from_date'];       
      $to_date=$_POST['to_date'];     
             
     
       
    
       $result1 = mysql_query("SELECT * FROM $tbl_name WHERE subject=$subject and orderr=$orderr and send_to=$send_to and distribution=$distribution and distribution2=$distribution2 and order_status=$order_status and datee BETWEEN $from_date and $to_date"); 
     
     ?>
     
     <table  align="center" border='1'  width="90%" height="30%" style=" font-size:18px;"  >
     <br> <br> <br>
     <caption> <font size="5"> reports  </caption>
     <?php
    while($row = mysql_fetch_array($result1))
    {
    echo "<tr><td >" . $row['notes']. "</td> <td>" .$row['order_id'] ."</td> <td>" .$row['order_note'] . "</td> <td>" .$row['order_status'] . "</td> <td>" .$row['distribution2'] . "</td><td>"
    .$row['distribution'] . "</td><td>" . $row['send_to'] . "</td> <td>" . $row['orderr'] . "</td> <td>" . $row['subject'] ."</td> <td>" . $row['book_no'] .
     "</td> <td>" . $row['datee'] . "</td><td> " . $row['order_id '].  "</td></tr>";
    
    
    }
    if (!$result1)
    {echo"errorrr";
    }
    
    ?>
    </table>   
    
    
      
    
    
    
    
    
    
    
    
  3. In Topic: I wrote my program ,, i need to know waht to do to make it run?

    Posted 30 Sep 2012

    import Stdin;
    import javax.swing.JOptionPane;
    
    class Employee 
    {
    	private String Id;
    	private String Name;
    	private String JopTitle;
    	private Double BasicSalary;
    	private Double OverTimeRate;
    	private Double OverTimeHours;
    	private Double GrossSalaryMonth;
    
    	public Employee()
    	{}
    	 
    	public Employee(String Id, String Name, String JopTitle, Double BasicSalary)
    	{
    		this.Id=Id;
    			this.Name=Name;
    			this.JopTitle=JopTitle;
    			this.BasicSalary=BasicSalary;
    	}
    		
    
    public class firstEmployee{
    public void main(String args[])
    {Employee firstEmployee=new Employee();//a
    
    
    	}}
    	
    	}
    



    the same error
    :(

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Member Title:
New D.I.C Head
Age:
22 years old
Birthday:
November 24, 1991
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