## h_h1354's Profile User Rating:

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1. #### In Topic: Min odd and min even of 6 entry without loop in c/c++

Posted 31 Jan 2012

```#include <iostream>
#include <cstdio>
using namespace std;
int main()
{
int a1,a2,a3,a4,a5,a6;
int odd_count=1,even_count=1;
int odd1,odd2,odd3,odd4,odd5,odd6;
int eve1,eve2,eve3,eve4,eve5,eve6;
int min_odd, min_even;

scanf("%d",&a1);
scanf("%d",&a2);
scanf("%d",&a3);
scanf("%d",&a4);
scanf("%d",&a5);
scanf("%d",&a6);

if (a1%2==0)
min_even=a1;

else if (a1%2!=0)
min_odd=a1;

if (a2%2==0 && a2<min_even)
min_even=a2;

else if (a2%2!=0 && a2<min_odd)
min_odd=a2;

if (a3%2==0 && a3<min_even)
min_even=a3;

else if (a3%2!=0 && a3<min_odd )
min_odd=a3;

if (a4%2==0 && a4<min_even)
min_even=a4;

else if (a4%2!=0 && a4<min_odd  )
min_odd=a4;

if (a5%2==0 && a5<min_even)
min_even=a5;

else if (a5%2!=0 && a5<min_odd  )
min_odd=a5;

if (a6%2==0 && a6<min_even)
min_even=a5;

else if (a6%2!=0 && a6<min_odd  )
min_odd=a6;

printf( "odd %d",min_odd);
printf( "odd %d",min_even);

system("pause");
}
```

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