Thank you for your responses r.stiltskin. !

  for(int i = 0; b > 56 ; i++) {
for(int b=i ; b> 56; i++){
}swap lowest into arr[i] }

any better? not sure if b is the right variable to call, or if i even assign letters to numbers.

Ok so as I understand I must find my largest number so far before I start sorting.

while(i < SIZE) {
		if(largestSoFar < values[i]) {
			largestSoFar = values[i];
			location = i;
		}
		i = i + 1;
	}
	cout << "The largest element was " << largestSoFar << " and was in location " << location << ".\n";

but then how do i exchange the largest value found with the value at the end and repeat the process without having to code a separate line for each sort? and then from there do I assign letters as my temporary variables??

thank you for the timely responses, I may be just confusing basics here...



I believe my for statement should look something like this, But I am Having troubles with my While statement. any help>

  for(int i = 0 ; i < 20; i++) {
for (int j = i ; j < 20 ; j++) { 
}
swap lowest into arr[i] 
}

right, I get the basic concept of sort selection. Moving the unsorted subsection left and sorted subsection right until numbers are numerically arranged. But what I don't understand is how to set the marker for the unsorted section at the end of the list, and how to move the marker as numbers are sorted. I realize the "end" is inside the array as opposed to SIZE but Im trying to swap the end with the largest value but i have no idea how to call a temporary variable or the best way to find the largest number on my list.