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  1. In Topic: Please answer my question.

    Posted 1 Feb 2013

    View Postmodi123_1, on 31 January 2013 - 10:47 PM, said:

    Sure.. you just need to install the right ACE/JET redistribution pack and it should be okay.

    https://www.microsof...s.aspx?id=13255
    http://support.micro...kb;en-us;239114

    Thank you sir! thanks a lot! =D

  2. In Topic: Why I can't connect to database?

    Posted 31 Jan 2013

    View Post_HAWK_, on 29 January 2013 - 09:19 PM, said:

    It appears you have not initialized the conn object. Not a great mystery use the New keyword like it states in the error.

    Dim co As New ClassObject 'example of initialization.


    This is a fundamental knowledge point for all your future works, please get a book and learn the basics - it will serve you well.


    THANK YOU SIR! I did it! I did it! I did it! Hooray! Thank you again! =D

  3. In Topic: Why I can't connect to database?

    Posted 29 Jan 2013

    View Postandrewsw, on 29 January 2013 - 06:44 PM, said:

    Remove the Try..Catch block to allow any error message(s) to be shown then let us know the error message(s) you receive.

    Sir! there is an error at

    IF .State = ConnectionState.Open Then .Close()
    `It says that NullExceptionRefrenceUnhandled

    Object refrence not set to an instance of an object.

    TroubleShooting Tips:

    Use the "new" keyword to create an object instance.
    Check to determine if the object is null before calling the method.
    Get general help for this exception.
    and so on. . 

    
#Region "Connection"
    Sub ConntoDB()
        Try
            With conn
                If .State = ConnectionState.Open Then .Close()
                .ConnectionString = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=votersAccounts.accdb"
                .Open()
            End With
        Finally
        End Try
    End Sub
#End Region


    Sir! please help me! =((

  4. In Topic: Why I can't connect to database?

    Posted 29 Jan 2013

    View Postandrewsw, on 29 January 2013 - 06:44 PM, said:

    Remove the Try..Catch block to allow any error message(s) to be shown then let us know the error message(s) you receive.

    ok, i'll try it sir.

  5. In Topic: hello can anyone here can help my simple problem?

    Posted 28 Jan 2013

    View PostMartyr2, on 27 January 2013 - 11:55 PM, said:

    For general practice in security it is best never to tell the user if it was their username or password that is wrong. This is because if someone is attacking the login and you are saying the username is incorrect a bunch of times and then suddenly tell the user that password is incorrect the attacker now knows a valid username to attack.

    Always use the line Your username and/or password is incorrect, please try again. That way the attacker never really knows if either of them is actually valid.

    Also the code you are presenting there is done in VB6 old syntax and is not how it is done anymore in VB.NET. For instance MsgBox should now be MessageBox.Show("message")

    So if you put this together you should have something like...

    Dim count as integer = 0

If count < 3 then
   If userTextbox.text = "username" and passTextbox.text = "password" then
       MessageBox.Show("Welcome!")
   Else
       MessageBox.Show("Your username and/or password is incorrect. Please try again.")
       count += 1
   End if
Else
   MessageBox.Show("You have been banned for 3 minutes.")
   ' Start timer if it hasn't been started, otherwise leave event
   ' At end of timer, reset count back to 0
End if


    This code above assumes you have it tied into a login button event some how. :)/>





    Thank you very much for your helpful tips and a very quick response. . . Good day! =D

    View Postandrewsw, on 28 January 2013 - 01:37 AM, said:

    The reason your original code wasn't working is because If..ElseIf requires ElseIf to be one word.

    http://msdn.microsof...y/752y8abs.aspx

    Yes! that is also my code error. . thank you! =D

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