4N63L-Z3R0's Profile
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In Topic: Comparing array to an int
Posted 2 Apr 2013
incomeptr is an int pointer and avgincome is an int.
Here is my program so far so you can see where I am at:
// Midterm_Survey_N.cpp : Defines the entry point for the console application. // This program belongs to NM. #include "stdafx.h" #include <iostream> using namespace std; // Function prototypes. void incomeAvg (int *, int *, int); void poverty (int *, int *, int); // Function 3 int main() { const int SIZE = 13; int id[SIZE]; // household id number - keep at 4 digits int income[SIZE]; // household annual income int memberNum[SIZE]; // household member number int c; // ***Assigned pointers*** ******************* // int *idptr; idptr = id; int *incomeptr; incomeptr = income; int *memberptr; memberptr = memberNum; // *********************** ****************** // cout << "Enter 4-digit household ID number.\n"; for (c = 0; c < SIZE; c++) { cout << "Household " << (c+1) << ": "; cin >> id[c]; } cout << "\nEnter household's annual income.\n"; for (c = 0; c < SIZE; c++) { cout << "Household " << (c+1) << ": $"; cin >> income[c]; } cout << "\nEnter number of members in household.\n"; for (c = 0; c < SIZE; c++) { cout << "Household " << (c+1) << ": "; cin >> memberNum[c]; } // Function calls. incomeAvg (incomeptr, idptr, SIZE); poverty (incomeptr, memberptr, SIZE); // Function call 3 return 0; } // Function headers. void incomeAvg (int *incomeptr, int *idptr, int SIZE) { int totalincome = 0, avgincome = 0; int c; // Total income (for average). for (c = 0; c < SIZE; c++) { totalincome += incomeptr[c]; } // Average income. for (c = 0; c < SIZE; c++) { avgincome = totalincome / SIZE; } // Display the average income. cout << "The average income between all households is: $" << avgincome << "." << endl; // Display the EXCEEDING incomes. cout << "-------Households that exceed the average income-------" << endl; cout << " Household ID Exceeding Income"; //////////////////////// // More to come here. // This is where I am having the trouble. //////////////////////// cout << endl; } void poverty (int *incomeptr, int *memberptr, int SIZE) { double pov, percentage; int c; // Formula to calculate poverty line. for (c = 0; c < SIZE; c++) { pov = 6500.00 + 750.00 * memberptr[c]; } // Calculates percentage of households UNDER poverty line. //////////////////////// // More to come here. // //////////////////////// } -
In Topic: Comparing array to an int
Posted 2 Apr 2013
I am trying to compare the numbers I have in the array to an average value. If there is a number, or multiple numbers, in the array that are greater than the average value then display those numbers.
There are no errors notified by my compiler, but I am not getting the output I want. I am getting the actual coded value of incomeptr[c] which is a messy combination of numbers and letters. I need a list of the greater-than-average values in the array. -
In Topic: Most frequent character in string
Posted 12 Mar 2013
Aaahh! Yes!! Thank you very much!
It is running perfectly now.
As I said before, shouldn't program while tired... Hahaha! -
In Topic: Most frequent character in string
Posted 12 Mar 2013
Yeah, that makes sense! I shouldn't do this while tired, hah.
I tried
if (arr[string1[c]] > max && arr[string1[c]] != ' ')
and am still having the same issue. -
In Topic: Most frequent character in string
Posted 12 Mar 2013
I noted that when I run this program, if I use a sentence like "Hello I am a moose" I get a blank as my most frequent character because the most frequent character is a space " ". I am fiddling with it to try and not count the spaces, but am having a hard time.
How could I add that it doesn't count spaces?
This isn't required for the assignment, I would just like to practice for personal skill.
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