alderaan's Profile
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Nov 21 2012 11:57 PM- Currently:
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In Topic: Cannot get respons when enter-key is pressed in textbox1.
Posted 21 Nov 2012
Momerath, on 21 November 2012 - 11:26 AM, said:If you've set the AcceptButton property of the form then the enter key will be captured by the form and not any of the controls on the form.
OK!
Thank you. I got it.
I have to get a button to the form and then set the "AcceptButton" property to use "button1" of the form - not the button property.
Then i can use Enter-key triggering the "button1" button.
I donīt really want a extra button in my form, and i think itīs a little crazy, but i works. No other methods work for me.
[code]
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace enterkey
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
string sometext;
sometext = textBox1.Text;
MessageBox.Show("You Wrote " + sometext);
//Compare entered text to a string
if(sometext=="hello world")
MessageBox.Show("string match");
else
MessageBox.Show("string mismatch");
}
}
}
]/code] -
In Topic: Cannot get respons when enter-key is pressed in textbox1.
Posted 21 Nov 2012
I get no respons at all.
Nothing is happening.
No error message.
If i use textBox1_TextChanged method i get a respons
in this example the key a is pressed.
What i want to do is write some text in textBox1 and press enter,
and then treat the text in textBox1 as a string.
using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace enterkey { public partial class Form1 : Form { public Form1() { InitializeComponent(); } private void textBox1_KeyDown(object sender, System.Windows.Forms.KeyEventArgs e) { if (e.KeyCode == Keys.Enter) MessageBox.Show("enter is pressed"); } private void textBox1_TextChanged(object sender, EventArgs e) { if(textBox1.Text == "a") MessageBox.Show("a is pressed"); } } } -
In Topic: Using backgroundworker to report progress with progressbar.
Posted 21 Nov 2012
Why would i need two progressbars.
Well i figured it out by myself.
This is the correct code (part of the modified code):
public partial class Form1 : Form { public Form1() { InitializeComponent(); // Set Minimum to 0 to represent the first row beeing processed. progressBar1.Minimum = 0; // Set the initial value of the ProgressBar. progressBar1.Value = 0; // Set the Step property to a value of 1 to represent each row beeing processed. progressBar1.Step = 1; // Calculate number of rows. System.Int32 calculaterows = dataGridViewDump.Rows.Count; // Set Maximum to the total number of rows beeing processed. progressBar1.Maximum = calculaterows-1; } void backgroundWorker1_DoWork(object sender, DoWorkEventArgs e) { Excel.Application xlApp; Excel.Workbook xlWorkBook; Excel.Worksheet xlWorkSheet; object misValue = System.Reflection.Missing.Value; xlApp = new Excel.Application(); xlWorkBook = xlApp.Workbooks.Add(misValue); xlWorkSheet = (Excel.Worksheet)xlWorkBook.Worksheets.get_Item(1); int i = 0; int j = 0; for (j = 0; j <= dataGridViewDump.ColumnCount - 1; j++) { xlWorkSheet.Cells[1, j + 1] = dataGridViewDump.Columns[j].Name; } for (i = 0; i <= dataGridViewDump.RowCount - 1; i++) { for (j = 0; j <= dataGridViewDump.ColumnCount - 1; j++) { DataGridViewCell cell = dataGridViewDump[j, i]; xlWorkSheet.Cells[i + 2, j + 1] = cell.Value; backgroundWorker1.ReportProgress(i); } } System.Threading.Thread.Sleep(1000); MessageBox.Show("Excel file created at desktop as dbasedump.xls"); } } -
In Topic: Using backgroundworker to report progress with progressbar.
Posted 20 Nov 2012
No other problems.
How do i report progress of i and j?
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