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- 19-April 13
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- Oct 10 2013 03:50 AM
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Posts I've Made
Posted 10 Oct 2013Thanks for reply me,
There are two separate solutions, but both used single DataBase,
I saved DataBase file(MS-Access) path in first project my.setting string,
now I want to read that DataBase file path from second project.
Posted 24 Sep 2013Thanks for it,
It can use,
but If more than one child forms opened (or child forms can be minimized),
I have to check frequently when any form open...Are there any forms opened(maximized) to hide, also minimized and close to show,
I can do it, Sir Please tell me, any easy way to do.
I want to use my Mdi form background, as our Computer Desktop wallpaper,(When any software open then wallpaper hide, again application close or minimized, wallpaper can see)
Posted 24 Sep 2013Sir,
There are no lot of codes,
those two forms has picture box and one form has Menu.
Private Sub NewToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles NewToolStripMenuItem.Click EnterPage.MdiParent = Me EnterPage.Show() End Sub
that's all code.
but, Here with I attached link for all project file with my error.
Please correct it,
My Project Sample
Posted 24 Sep 2013Sir,
Thanks for Reply me, sorry sir my English not good.
I explain my all thing..
I created two forms. In First (Form1) "IsMdiContainer" change to "True", then I created Menu items for it. After I put picture box on Form1. (Dark Ash color background area on Form1).
second form (Form2) created with normals controls.
I want to show / Close - "Form2" from Menu in "Form1"
then I coded to "MenuItem_Click" like that earlier I said.
From this code "Form2" opened and "Form1" hide, but pictures of "Form1" still appear over the "Form2" like this attachment.
Posted 23 Sep 2013Thanks for clarification, that what I need,
I call to Child form, From Mdi - Menu, I just create Picture box on Mdi Form and add images into it
I code to Mdi - menu Like this, (when Click menu items form2 will open.),
I not use code to hide Mdi form.
Form2.MdiParent = Me Form2.Show()
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