Subscribe to Stuck in an Infiniteloop
2 Comments
You ever run across a problem that you just say, "why?" And then you had to write a quick snippet to solve it?
This was mine as I was doing my near midnight DIC browsing. [Hey ooooo!]
Behold, a solution!
This was mine as I was doing my near midnight DIC browsing. [Hey ooooo!]
Behold, a solution!
str = "aaabbbcbbaaa"
pairs = []
counter = 1
(0..(str.length-1)).each do |i|
if not str[i] == str[i+1]
pairs << [ str[i], counter ]
counter = 1
else
counter = counter + 1
end
end
print pairs
Quote
$ ruby encode.rb
[["a", 3], ["b", 3], ["c", 1], ["b", 2], ["a", 3]]
[["a", 3], ["b", 3], ["c", 1], ["b", 2], ["a", 3]]
Categories: Uncategorized
Share This Entry:
2 Comments On This Entry
Page 1 of 1
Lemur
04 May 2013 - 12:49 AM
http://www.ruby-doc....Enumerable.html
Enumerable has a number of methods that work quite well to simplify problems of this and similar natures. Inject is especially amazing.
Enumerable has a number of methods that work quite well to simplify problems of this and similar natures. Inject is especially amazing.
KYA
05 May 2013 - 11:41 AM
Looking at the doc for inject, I'm not entirely sure if it would be helpful in this regard. You need to be aware of the next element in the sequence which inject doesn't appear to allow unless you let the block be aware of the string globally.
Page 1 of 1
← January 2022 →
| S | M | T | W | T | F | S |
|---|---|---|---|---|---|---|
| 1 | ||||||
| 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| 9 | 10 | 11 | 12 | 13 | 14 | 15 |
| 16 | 17 | 18 | 19 | 20 | 21 | 22 |
| 23 | 24 | 25 | 26 | 27 | 28 | 29 |
| 30 | 31 |
Tags
My Blog Links
Recent Entries
Recent Comments
Search My Blog
15 user(s) viewing
15 Guests
0 member(s)
0 anonymous member(s)
0 member(s)
0 anonymous member(s)
| 