[ClanguageLearner]

Hello everyone,

I need some help with one of the warnings I have been getting. My program compiles just fine, however, I get the following warning:

warning C4996: 'scanf': This function or variable may be unsafe. Consider using scanf_s instead. . can someone please explain what difference does it make by including scanf_s vs. scanf?

Here my code:

#include <stdio.h>

int main(void)

{
int n=0;
int nO=0;
int nT=0;
int nTh=0;
int nF=0;
int nFi=0;




printf("Please enter a number :");
scanf("%d",&n);


nO = n/10000;
nT = (n % 10000) /1000;
nTh = (n % 1000) /100;
nF = (n % 100) /10;
nFi = n % 10;



printf("\n%4d%4d%4d%4d%4d\n", nO, nT, nTh, nF, nFi);
printf("\n%4d%4d%4d\n", nTh, nF, nFi);
printf("\n%4d%\n", nFi);

return 0;

}

I am using Microsoft Visual C++ 2008 expression edition.

This post has been edited by ClanguageLearner: 19 July 2009 - 09:03 PM

[ClanguageLearner]

thanks c.user but this does not help much

[Ancient Dragon]

You are using a Microsoft compiler. Microsoft, in its infinite wisdom, declared many C functions depreciated, and it did that without authority of the C or C++ standards committee. Those functions are not depreciated.

You can suppress that warning message like this:

#pragma warning(disable: 4996)

More information here

But I won't debate the usefullness of those substitute Microsoft-Specific functions, such as scanf_s, because they are safer than the originals, and in time they may find their way into the C and C++ standards. But that is not yet, so if you use them you will have non-portable programs.

This post has been edited by Ancient Dragon: 19 July 2009 - 09:28 PM

[codefreak.]

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