[hd_pulse]

  # define A 100
# define M 100
#include<ctype.h>
#include<stdio.h>
#include<string.h>
#include<conio.h>
void main()
{
char a[M];
clrscr();
gets(a);
int k[A][A],r=0,c=0,i,j,l;
for(i=0;i<strlen(a);i++)
{
if(a[i]!=' ')
{
k[r][c]=a[i];
c++;
}
else
{
k[r][c]='\0';
r++;
c=0;
}
}
printf("c=%d \n",c);
printf("r=%d \n",r);
for(  i=0;i<=r;i++)
{
printf("%s\n",k[i]);
}
getch();
} 

in the above program I want to print each string in different line.
say if the given string is "john is a hardworking student" I'm trying to print this way...

john
is
a
hardworking
student

but my output is coming like this...
j
i
a
h
s
i.e first character of each string in the sentence.

What is the probable error i m making????
plz I'm new to c programming help me!!!

regards

[IngeniousHax]

try searching the string for a null character, such as a... space, or newline marker.

if(/*something*/ == '\0')
	printf(/*print the stuff*/)

[hd_pulse]

i've made such little changes in the prorgam

# define A 100
# define M 100
#include<ctype.h>
#include<stdio.h>
#include<string.h>
#include<conio.h>
void main()
{
char a[M];
clrscr();
gets(a);
int k[A][A],r=0,c=0,i,j,l;
for(i=0;i<strlen(a);i++)
{
if(a[i]!=' ')
{
k[r][c]=a[i];
c++;
}
else
{
k[r][c]='\0';
r++;
c=0;
}
}
printf("c=%d \n",c);
printf("r=%d \n",r);
/*for(  i=0;i<=r;i++)
{
printf("%s\n",k[i]);
}*/
for(  i=0;i<=r;i++)
{
for(j=0;j<=c;j++)
{
if(k[i][j]=='\0')
{
printf("here%s\n",k[i]);
}
}
}
getch();
} 

now the output is
j
i
a

for such string..."john is a hardworking student" not what I wan't to get.

Plz help anything else needs to be changed so please post !!
thanks