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Visual Basic 6 -Determining Each Character in VB Very Handy Rate Topic: -----

#1 Xenon   User is offline

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Posted 26 October 2005 - 02:24 AM

Examining Characters in a string.

Note : - i ve explained the code Block by block, but when you try it in VB keep it in the SAME ORDER that follows in this tutorial.

The following application verifies the characters in a given string and returns details about the string.

First of all make the following interface. i havent changed the name of the form, so the form name is "form1", but only the caption.

Posted Image

name the text box as txtStr
and the command button as cmdVerify

Then add the following code.

In the following general declaration, we use :-
Option Explicit
Dim strl As String
Dim chrl As String * 1 ‘ Specifies the length to one digit.
Dim ctr As Integer

Dim letters As Integer
Dim UpCase As Integer
Dim LoCase As Integer
Dim digits As Integer
Dim blanks As Integer
Dim others As Integer

where the variable :-
strl – stores the string passed from the textbox.
chrl – stores extracted character from the string.
ctr – the position number from which the character is

Letters (a, e, t, y, f, s etc) – stores the number of letters counted in string.

UpCase – Stores the number of Uppercase letters in string.
LoCase – stores the number of Lowercase letters in string.
digits ( 0 to 9)– stores the number of digits counted in string.

blanks (“ “)– stores the number of blank spaces in string.

others (%#^&*<>?: =)– stores the number of special characters.

Now add this code in the click event of the command button named cmdVerify :-

Private Sub cmdVerify_Click()

‘ß This code clears the form screen of earlier prints so that you can start printing from the first line.
 ‘ß This code refreshes the form.

‘ Now setting the initial values of all variables to zero.

letters = 0
digits = 0
blanks = 0
others = 0

‘ Passing the textbox string to the variable.
strl = txtStr.Text

Now carefully look at the code that is preceding , ill explain it line by line.
For ctr = 1 To Len(strl)
chrl = Mid(strl, ctr, 1)

In the above code,
the first line is a part of a for loop, that goes on from one till the length of the string is achieved.

The second line then uses the MID function to extract the particular character from the sting at a time. Now the general syntax of the MID function is,

Mid(“String”, Start Pos,[Length])

Where “String” is the String on which you are going to perform the MID function, Start Pos is the position from which the first character is to be extracted, and length is the number of characters to be extracted from the string preceding from the Start Pos, including the Start Pos Character.

Now coming to the next par of the code :-
If (UCase(chrl) >= "A" And UCase(chrl) <= "Z") Then
letters = letters + 1

The above 2 lines of code can be described as follows,

We take the extracted character ‘chrl’ and compare it to all the alphabets from A to Z, keeping the character ‘ignore-case’
If IT IS a letter, then the value of the variable ‘letter’ is increased by one in the next line (letters = letters + 1)

In the Next 5 lines of code, it determines whether it is an uppercase letter or a lowercase one,(only if it is a letter)
If ((chrl) >= "A" And (chrl) <= "Z") Then
UpCase = UpCase + 1
ElseIf ((chrl) >= "a" And (chrl) <= "z") Then
LoCase = LoCase + 1
End If

This part of the code compares the character to be digit from 0 to 9 or not. If it is a digit increase the value of the variable ‘digit’ by one.
ElseIf (chrl >= "0" And chrl <= "9") Then
digits = digits + 1

This part of the code compares the character to be a blank space or not. If it is a blank space increase the value of the variable ‘blanks’ by one.
ElseIf (chrl = " ") Then
blanks = blanks + 1

Now the only character that can exist in a visible string are the special characters, if the character fails all the above tests, then it is a special character.
others = others + 1
End If
‘End the FOR LOOP.
Next ctr

Now we print all the details of the variables onto the form in a nice manner.
Print " -------------------------------------------------------"
Print " Details about the string you have entered "
Print " ---------------------------------------------------------"
Print " Number of letters is =  " & letters
Print " Number of Lower case letters is =  " & LoCase
Print " Number of Uppercase letters is  =  " & UpCase
Print " ----------------------------------------------------------"
Print " Number of digits is = " & digits
Print " Number of blank spaces is = " & blanks
Print " Number of special characters is = " & others
Print " -------------------------------------------------------------"
Print " Total Length of String is "; Len(txtStr.Text); " characters "
Print " -------------------------------------------------------------"
End Sub

of course, the END SUB will automatically be generated when you double click the command button in design time, hence it wont be missed out.

Hope this Tutorial is helpful :)

This post has been edited by Xenon: 28 October 2005 - 08:51 AM

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Replies To: Visual Basic 6 -Determining Each Character in VB

#2 oXiDe   User is offline

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Posted 22 November 2007 - 03:12 PM

hi i think you forgot to do LoCase = 0 & UpCase = 0 at the beginning because if u keep pressing Verify String the # of uppercase & lowercase keeps going up :l . still this tutorial pwns :D
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