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#1 ice-t   User is offline

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Search in a generic linked list

Post icon  Posted 25 December 2009 - 09:47 AM

i want to make a search method to return a node of the list.
the linked list is a generic linked list List<T> and i want to return a node of type T.
this is what I tried.
list<T> *search(People *x) // I tried search(T *s) too
		   list<T> *q = root_list;
		  if(q!=NULL && strcmp(q->element,x->name)==0)
			return q;
		  q = q->next;
 return NULL;

People is a class which has name as a private.I get this error. Cannot convert People* to const char*, and after trying different syntax sometimes i get People::name member is not accesible

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Replies To: Search in a generic linked list

#2 Dogstopper   User is offline

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Re: Search in a generic linked list

Posted 25 December 2009 - 10:17 AM

Because name is a private variable, you cannot access it in this way. You will have to make a getter method in the People class, like this:
class People 
		char[] name;
		 char[] getName() {
			 return name;

Note, I havnt done C++ in a long while and it's probably not char[], but there is the general idea. You may also wish to use the string class: http://www.cprogramm...ial/string.html
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