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MASM : 1024-Bit Arithmetic Functions : Part III

#1 Martyn.Rae   User is offline

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Posted 31 March 2011 - 01:29 PM

MASM : 1024-bit Arithmetic Functions : Part III


The ability to provide arithmetic on integers larger than the CPU register width has always provided me with endless hours of fun in assembly. Being a kind and generous person, I have decided to share that enjoyment with you all, by providing a set of three tutorials on addition, subtraction, multiplication and division on binary numbers that are very stupidly large!

This third tutorial concerns itself with 1024-bit unsigned division providing a 1024-bit quotient and 1024-bit remainder.


Given a 1024-bit dividend and a 1024 bit divisor, compute the 1024-bit quotient and 1024 bit remainder. We shall use the long division method by:

1. Clear the remainder
2. Left shift the remainder by 1
3. Left shift the dividend by 1 (the most significant bit is shifted out and into the carry flag)
4. If the carry flag is set, then set the least significant bit of the remainder
5. Shift the quotient left by 1
6. Compare the remainder with the divisor
7. If the remainder is greater than or equal to the divisor then subtract the divisor from the remainder and set the least significant bit of the quotient
8. Repeat steps 2 to 7 1023 times

1024-bit Division

Here then, is the 1024-bit division code.

Div1024				proc		num1:dword, num2:dword, result:dword, remainder:dword
					local		num1_shift[32]:DWORD, partial[32]:DWORD
					local		num2_shift[32]:DWORD

					xor			eax, eax
					mov			edi, remainder
					mov			ecx, 32
					rep			stosd
					mov			edi, result
					mov			ecx, 32
					rep			stosd
					mov			esi, num1
					lea			edi, num1_shift
					mov			ecx, 32
					rep			movsd
					mov			esi, remainder
					mov			edi, result
					mov			ecx, 1024
Div1024_loop:		invoke		Shl1024, remainder
					invoke		Shl1024, ADDR num1_shift
					jnc			Div1024_1
					bts			dword ptr [esi+124], 0
Div1024_1:			invoke		Shl1024, result
					invoke		Sub1024, remainder, num2, ADDR partial
					jb			Div1024_2
					invoke		Sub1024, remainder, num2, remainder
					bts			dword ptr [edi+124], 0
Div1024_2:			dec			ecx
					jnz			Div1024_loop
Div1024				endp


The routines that I have provided over these three tutorials are, of course little or no use in the real world. Their purpose is to demonstrate the versatility and extensibility of the x86 machine code instruction set and perhaps inspire the reader to investigate it for themselves.

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